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RoseRoque
 2 years ago
Find the value of c such that the point P(a, b) lies on the graph of the function f.
f(x) = x*sqrt(36 − x^2) + c; P(5, 10)
RoseRoque
 2 years ago
Find the value of c such that the point P(a, b) lies on the graph of the function f. f(x) = x*sqrt(36 − x^2) + c; P(5, 10)

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primeralph
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1367696013938:dw

surjithayer
 2 years ago
Best ResponseYou've already chosen the best response.0for f(x) to be defined36x^2>=0,36>=x^2, or x^2<=36 \[\left x \right\le6,6 \le x \le6\] c can have any real value \[but x \in \left( 6,6 \right)\]

RoseRoque
 2 years ago
Best ResponseYou've already chosen the best response.0Can ANYONE help...both people who have posted are wrong and I need help preparing for my Final Exam
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