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RoseRoque
Find the value of c such that the point P(a, b) lies on the graph of the function f. f(x) = x*sqrt(36 − x^2) + c; P(5, 10)
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for f(x) to be defined36-x^2>=0,36>=x^2, or x^2<=36 \[\left| x \right|\le6,-6 \le x \le6\] c can have any real value \[but x \in \left( -6,6 \right)\]
Can ANYONE help...both people who have posted are wrong and I need help preparing for my Final Exam