## anonymous 3 years ago Find the value of c such that the point P(a, b) lies on the graph of the function f. f(x) = x*sqrt(36 − x^2) + c; P(5, 10)

1. primeralph

|dw:1367696013938:dw|

2. anonymous

for f(x) to be defined36-x^2>=0,36>=x^2, or x^2<=36 $\left| x \right|\le6,-6 \le x \le6$ c can have any real value $but x \in \left( -6,6 \right)$

3. anonymous

@jim_thompson5910

4. anonymous

@Callisto

5. anonymous

Can ANYONE help...both people who have posted are wrong and I need help preparing for my Final Exam