Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

tkhunnyBest ResponseYou've already chosen the best response.1
Looks like a good "paying attention" problem. What have you tried? This? \(\dfrac{d}{dt}2^{t}\cdot 2\cdot\sin^{1}(2t+1)\) Personally, I would rewrite it just a little. This? \(\dfrac{d}{dt}2^{t+1}\cdot\sin^{1}(2t+1)\)
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
\[d/dt (2^t \sin ^{1}(2t+1)\]
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
product rule and chain rule?
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
Okay, so no extra 2 and there is no need or temptation to rewrite it. Great. You have the idea. Let's see what you get. Hint: \(\dfrac{d}{dt}2^{t} = 2^{t}\cdot\log(2)\)
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
False. You had a clue a minute ago. Get it back.
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
chain rule for each numbers?
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
Hint: \(\dfrac{d}{dt}\sin^{1}(t) = \dfrac{1}{\sqrt{1t^{2}}}\) That's about all you need.
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
Stop asking questions and start writing the derivative.
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
\(\dfrac{d}{dt}f(t)\cdot g(t) = f(t)\cdot g'(t) + g(t)\cdot f'(t)\) Go!
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
That's part of it. Keep going.
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
product rules? but it does not make sense \[2^t \sin^{1} (2t+1) \] three parts. the product has two/ f(x)g(x)
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
If there where three, you could just group them and make pairs. There are only two. \(2^{t}\) \(\sin^{1}(2t+1) = asin(2t+1)\)
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
\[2^t*(asin(2t+1)'+(asin(2t+1)(2^t)'\] ?
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
There's that question again. Move forward. Do NOT stop to ask every time you flinch! Keep going!
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
I want to make sure that i am doing right. so i dont need to rise off all my effort and time writting wrong equation
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
Right. I understand your motivation. I am also telling you that it is holding you back. You have far too much fear. Learn the right things. Go the right direction. Go with confidence. What's next?
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
\[(2^t)(1/\sqrt(1t)*dx (2t+1)+asin(2t+1)(2^tlong(2)\]
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
So Close!! \(\dfrac{d}{dt}asin(t) = \dfrac{1}{\sqrt{1t^{2}}}\) \(\dfrac{d}{dt}asin(2t+1) = \dfrac{1}{\sqrt{1(2t+1)^{2}}}\cdot 2\)
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
See! That was very good. No need to fear. Just pay a little better attention.
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
\[2^t \frac{ 2 }{ \sqrt{1(2t+1)}}+(\sin^{1}(2t+1)(2^t* \log (2)) \]
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
Missed the "squared" in the square root. Otherwise, perfect.
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
Already showed you that. Pay better attention. \(\dfrac{2}{\sqrt{1  (2t+1)^{2}}}\)
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
Now, seriously. This is where I look you in the eye and ask you if you are in the right class, if you are truly dedicated to this course, if you think you can gain the confidence to move forward  and various other questions about your mental health. Work hard. You'll get it!
 11 months ago

Dodo1Best ResponseYou've already chosen the best response.0
Thank you very much tkhunny. i will work hard and thank you for your advice.
 11 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.