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Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
@tkhunny please help!
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Looks like a good "paying attention" problem. What have you tried? This? \(\dfrac{d}{dt}2^{t}\cdot 2\cdot\sin^{1}(2t+1)\) Personally, I would rewrite it just a little. This? \(\dfrac{d}{dt}2^{t+1}\cdot\sin^{1}(2t+1)\)
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
\[d/dt (2^t \sin ^{1}(2t+1)\]
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
product rule and chain rule?
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Okay, so no extra 2 and there is no need or temptation to rewrite it. Great. You have the idea. Let's see what you get. Hint: \(\dfrac{d}{dt}2^{t} = 2^{t}\cdot\log(2)\)
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
mmm i have no clue.
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
False. You had a clue a minute ago. Get it back.
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
chain rule for each numbers?
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Hint: \(\dfrac{d}{dt}\sin^{1}(t) = \dfrac{1}{\sqrt{1t^{2}}}\) That's about all you need.
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Stop asking questions and start writing the derivative.
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
\(\dfrac{d}{dt}f(t)\cdot g(t) = f(t)\cdot g'(t) + g(t)\cdot f'(t)\) Go!
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
\[d/dt (2t+1)= (2)\]
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
That's part of it. Keep going.
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
product rules? but it does not make sense \[2^t \sin^{1} (2t+1) \] three parts. the product has two/ f(x)g(x)
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
If there where three, you could just group them and make pairs. There are only two. \(2^{t}\) \(\sin^{1}(2t+1) = asin(2t+1)\)
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
\[2^t*(asin(2t+1)'+(asin(2t+1)(2^t)'\] ?
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
There's that question again. Move forward. Do NOT stop to ask every time you flinch! Keep going!
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
I want to make sure that i am doing right. so i dont need to rise off all my effort and time writting wrong equation
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Right. I understand your motivation. I am also telling you that it is holding you back. You have far too much fear. Learn the right things. Go the right direction. Go with confidence. What's next?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
\[(2^t)(1/\sqrt(1t)*dx (2t+1)+asin(2t+1)(2^tlong(2)\]
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
So Close!! \(\dfrac{d}{dt}asin(t) = \dfrac{1}{\sqrt{1t^{2}}}\) \(\dfrac{d}{dt}asin(2t+1) = \dfrac{1}{\sqrt{1(2t+1)^{2}}}\cdot 2\)
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
See! That was very good. No need to fear. Just pay a little better attention.
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
\[2^t \frac{ 2 }{ \sqrt{1(2t+1)}}+(\sin^{1}(2t+1)(2^t* \log (2)) \]
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Missed the "squared" in the square root. Otherwise, perfect.
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Already showed you that. Pay better attention. \(\dfrac{2}{\sqrt{1  (2t+1)^{2}}}\)
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
ok, thank you
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Now, seriously. This is where I look you in the eye and ask you if you are in the right class, if you are truly dedicated to this course, if you think you can gain the confidence to move forward  and various other questions about your mental health. Work hard. You'll get it!
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
Thank you very much tkhunny. i will work hard and thank you for your advice.
 one year ago
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