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RadEn
 one year ago
Best ResponseYou've already chosen the best response.1for Q.a use the identity : cosAcosB + sinAsinB = cos(AB)

u0860867
 one year ago
Best ResponseYou've already chosen the best response.0i got 24 which is right

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1for Q.b use the identity : sinAcosB  cosAsinB = sin(AB), multiply by 1 to both sides, giving us cosAsinB  sinAcosB =  sin(AB)

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1in this case, given A = 17 and B = 7

u0860867
 one year ago
Best ResponseYou've already chosen the best response.0for b will the answer be 10

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1hmmm.... cosAsinB  sinAcosB =  sin(AB) put A= 17 and B=7 cos17sin7  sin17cos7 =  sin(177) cos17sin7  sin17cos7 =  sin10 then use the identity : sinx = sin(x) so, we get sin10 = sin(10) you were right :)

u0860867
 one year ago
Best ResponseYou've already chosen the best response.0and how do we do part 3 i got the wrong answer for it just have once chance left on it

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1do like Q.b for Q.c i think u can solve this, now :)

u0860867
 one year ago
Best ResponseYou've already chosen the best response.0@RadEn i got the wrong answer again for part 3

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1hmmm.. cos3sin(2)  cos2sin3 = cos3sin2  cos2sin3 =  {cos3sin2 + cos2sin3} we have to use the identity cosAsinB + cosBsinA = sin(A+B) so,  {cos3sin2 + cos2sin3} =  sin(3+2) = sin5 again, use the identity sinx =sinx now we have sin5 = sin(5)
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