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u0860867
 2 years ago
pls help urgent help needed
u0860867
 2 years ago
pls help urgent help needed

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RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1for Q.a use the identity : cosAcosB + sinAsinB = cos(AB)

u0860867
 2 years ago
Best ResponseYou've already chosen the best response.0i got 24 which is right

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1for Q.b use the identity : sinAcosB  cosAsinB = sin(AB), multiply by 1 to both sides, giving us cosAsinB  sinAcosB =  sin(AB)

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1in this case, given A = 17 and B = 7

u0860867
 2 years ago
Best ResponseYou've already chosen the best response.0for b will the answer be 10

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1hmmm.... cosAsinB  sinAcosB =  sin(AB) put A= 17 and B=7 cos17sin7  sin17cos7 =  sin(177) cos17sin7  sin17cos7 =  sin10 then use the identity : sinx = sin(x) so, we get sin10 = sin(10) you were right :)

u0860867
 2 years ago
Best ResponseYou've already chosen the best response.0and how do we do part 3 i got the wrong answer for it just have once chance left on it

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1do like Q.b for Q.c i think u can solve this, now :)

u0860867
 2 years ago
Best ResponseYou've already chosen the best response.0@RadEn i got the wrong answer again for part 3

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1hmmm.. cos3sin(2)  cos2sin3 = cos3sin2  cos2sin3 =  {cos3sin2 + cos2sin3} we have to use the identity cosAsinB + cosBsinA = sin(A+B) so,  {cos3sin2 + cos2sin3} =  sin(3+2) = sin5 again, use the identity sinx =sinx now we have sin5 = sin(5)
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