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anonymous
 3 years ago
Find the position function s(t) from the given velocity or acceleration function and initial value(s). Assume that units are feet and seconds. v(t) = 40 – sin t, s(0) = 2
anonymous
 3 years ago
Find the position function s(t) from the given velocity or acceleration function and initial value(s). Assume that units are feet and seconds. v(t) = 40 – sin t, s(0) = 2

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tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1Position Function: \(x(t) = \int\limits_{0}^{t}v(r)\;dr\) Go!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I got 1 is that correct?

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1No, it should have a 't' in it. What did you get for \(\int 40  \sin(t)\;dt\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I got (40  sin(t)) (x)

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1Maybe \(x(t) = 40t + \cos(t) + C\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then i substitute 2 right?

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1Sorry, I've been using x(t). I see the problem statement has specified s(t). \(s(t) = 40t + \cos(t) + C\) No, substitute t = 0, so that s(0) = 2. This establishes the values of "C".
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