## onegirl Group Title Find the position function s(t) from the given velocity or acceleration function and initial value(s). Assume that units are feet and seconds. v(t) = 40 – sin t, s(0) = 2 one year ago one year ago

1. tkhunny Group Title

Position Function: $$x(t) = \int\limits_{0}^{t}v(r)\;dr$$ Go!

2. onegirl Group Title

I got -1 is that correct?

3. tkhunny Group Title

No, it should have a 't' in it. What did you get for $$\int 40 - \sin(t)\;dt$$

4. onegirl Group Title

I got (40 - sin(t)) (x)

5. tkhunny Group Title

dt not dx.

6. tkhunny Group Title

Maybe $$x(t) = 40t + \cos(t) + C$$

7. onegirl Group Title

ok

8. onegirl Group Title

then i substitute 2 right?

9. tkhunny Group Title

Sorry, I've been using x(t). I see the problem statement has specified s(t). $$s(t) = 40t + \cos(t) + C$$ No, substitute t = 0, so that s(0) = 2. This establishes the values of "C".

10. onegirl Group Title

ohh okay got you