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onegirl
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Find the position function s(t) from the given velocity or acceleration function and initial value(s). Assume that units are feet and seconds. v(t) = 40 – sin t, s(0) = 2
 one year ago
 one year ago
onegirl Group Title
Find the position function s(t) from the given velocity or acceleration function and initial value(s). Assume that units are feet and seconds. v(t) = 40 – sin t, s(0) = 2
 one year ago
 one year ago

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tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Position Function: \(x(t) = \int\limits_{0}^{t}v(r)\;dr\) Go!
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
I got 1 is that correct?
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
No, it should have a 't' in it. What did you get for \(\int 40  \sin(t)\;dt\)
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
I got (40  sin(t)) (x)
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
dt not dx.
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Maybe \(x(t) = 40t + \cos(t) + C\)
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
then i substitute 2 right?
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Sorry, I've been using x(t). I see the problem statement has specified s(t). \(s(t) = 40t + \cos(t) + C\) No, substitute t = 0, so that s(0) = 2. This establishes the values of "C".
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
ohh okay got you
 one year ago
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