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onegirl

  • 2 years ago

Find the position function s(t) from the given velocity or acceleration function and initial value(s). Assume that units are feet and seconds. v(t) = 40 – sin t, s(0) = 2

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  1. tkhunny
    • 2 years ago
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    Position Function: \(x(t) = \int\limits_{0}^{t}v(r)\;dr\) Go!

  2. onegirl
    • 2 years ago
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    I got -1 is that correct?

  3. tkhunny
    • 2 years ago
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    No, it should have a 't' in it. What did you get for \(\int 40 - \sin(t)\;dt\)

  4. onegirl
    • 2 years ago
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    I got (40 - sin(t)) (x)

  5. tkhunny
    • 2 years ago
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    dt not dx.

  6. tkhunny
    • 2 years ago
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    Maybe \(x(t) = 40t + \cos(t) + C\)

  7. onegirl
    • 2 years ago
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    ok

  8. onegirl
    • 2 years ago
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    then i substitute 2 right?

  9. tkhunny
    • 2 years ago
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    Sorry, I've been using x(t). I see the problem statement has specified s(t). \(s(t) = 40t + \cos(t) + C\) No, substitute t = 0, so that s(0) = 2. This establishes the values of "C".

  10. onegirl
    • 2 years ago
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    ohh okay got you

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