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Find the position function s(t) from the given velocity or acceleration function and initial value(s). Assume that units are feet and seconds. v(t) = 40 – sin t, s(0) = 2
 11 months ago
 11 months ago
Find the position function s(t) from the given velocity or acceleration function and initial value(s). Assume that units are feet and seconds. v(t) = 40 – sin t, s(0) = 2
 11 months ago
 11 months ago

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tkhunnyBest ResponseYou've already chosen the best response.1
Position Function: \(x(t) = \int\limits_{0}^{t}v(r)\;dr\) Go!
 11 months ago

onegirlBest ResponseYou've already chosen the best response.0
I got 1 is that correct?
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
No, it should have a 't' in it. What did you get for \(\int 40  \sin(t)\;dt\)
 11 months ago

onegirlBest ResponseYou've already chosen the best response.0
I got (40  sin(t)) (x)
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
Maybe \(x(t) = 40t + \cos(t) + C\)
 11 months ago

onegirlBest ResponseYou've already chosen the best response.0
then i substitute 2 right?
 11 months ago

tkhunnyBest ResponseYou've already chosen the best response.1
Sorry, I've been using x(t). I see the problem statement has specified s(t). \(s(t) = 40t + \cos(t) + C\) No, substitute t = 0, so that s(0) = 2. This establishes the values of "C".
 11 months ago
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