## onegirl one year ago Find the position function s(t) from the given velocity or acceleration function and initial value(s). Assume that units are feet and seconds. v(t) = 40 – sin t, s(0) = 2

1. tkhunny

Position Function: $$x(t) = \int\limits_{0}^{t}v(r)\;dr$$ Go!

2. onegirl

I got -1 is that correct?

3. tkhunny

No, it should have a 't' in it. What did you get for $$\int 40 - \sin(t)\;dt$$

4. onegirl

I got (40 - sin(t)) (x)

5. tkhunny

dt not dx.

6. tkhunny

Maybe $$x(t) = 40t + \cos(t) + C$$

7. onegirl

ok

8. onegirl

then i substitute 2 right?

9. tkhunny

Sorry, I've been using x(t). I see the problem statement has specified s(t). $$s(t) = 40t + \cos(t) + C$$ No, substitute t = 0, so that s(0) = 2. This establishes the values of "C".

10. onegirl

ohh okay got you