Find the position function s(t) from the given velocity or acceleration function and initial value(s). Assume that units are feet and seconds. v(t) = 40 – sin t, s(0) = 2
Sorry, I've been using x(t). I see the problem statement has specified s(t).
\(s(t) = 40t + \cos(t) + C\)
No, substitute t = 0, so that s(0) = 2. This establishes the values of "C".