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yolifuentes67
 one year ago
Best ResponseYou've already chosen the best response.0*** I am assuming that by (cos 2x  1) you mean [cos(2x)  1] . It's an indeterminate form 0/0 , so you can use L'Hopital's rule (differentiate numerator and denominator separately). [ cos(2x)  1 ] / [ 1  cos(3x) ] lim x > 0 = [  2sin(2x) ] / 3sin(3x) lim x > 0 That is also an indeterminate form 0/0 , so apply L'Hopital's rule again : = [  4cos(2x) ] / 9cos(3x) lim x > 0 = ( 4 / 9)  Here's a zoomedin portion of the graph of f(x) = [ cos(2x)  1 ] / [ 1  cos(3x) ] You can see the graph passing through the point ( 0 , 4/9 )

morganKING
 one year ago
Best ResponseYou've already chosen the best response.0were did 3x come from

4kec4
 one year ago
Best ResponseYou've already chosen the best response.0@morganKING i am getting 1 for the limit of this one, but when i graph i am getting f(t)=3, as t approaches 0

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Are you having trouble finding the derivative? That is the only scenario I can see here since it tells you to use lhospital.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1let f(t)=t(1cos(t)) and g(t)=tsin(t) f(0)=0 and g(0)=0 since we have 0/0 we can use l'hopital rule (i think it is much easier to multiply the bottom by 1+sin(t) by whateves; it doesn't say to do that) Do limt>0 (f'/g') since we have f/g=0/0

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Not for your problem you asked about.

morganKING
 one year ago
Best ResponseYou've already chosen the best response.0yeah the derivative confused me @myininaya but not sure

morganKING
 one year ago
Best ResponseYou've already chosen the best response.0aw k gona try again

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1let f(t)=t(1cos(t)) and g(t)=tsin(t) Recall this above f(t)=ttcos(t) f'(t)=(ttcos(t))'=(t)'(tcos(t))' Derivative of t is easy For finding the derivative of tcos(t) you need the product rule. g'(t) is a bit easier to find.

morganKING
 one year ago
Best ResponseYou've already chosen the best response.0ZZZ dont get this keep on getting 0/0

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1You should not getting 0/0 after differentiating three times.
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