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lim
t  0 (t(1cos(t))/(t sin(t))
use using the lhoptialrule
 11 months ago
 11 months ago
lim t  0 (t(1cos(t))/(t sin(t)) use using the lhoptialrule
 11 months ago
 11 months ago

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yolifuentes67Best ResponseYou've already chosen the best response.0
*** I am assuming that by (cos 2x  1) you mean [cos(2x)  1] . It's an indeterminate form 0/0 , so you can use L'Hopital's rule (differentiate numerator and denominator separately). [ cos(2x)  1 ] / [ 1  cos(3x) ] lim x > 0 = [  2sin(2x) ] / 3sin(3x) lim x > 0 That is also an indeterminate form 0/0 , so apply L'Hopital's rule again : = [  4cos(2x) ] / 9cos(3x) lim x > 0 = ( 4 / 9)  Here's a zoomedin portion of the graph of f(x) = [ cos(2x)  1 ] / [ 1  cos(3x) ] You can see the graph passing through the point ( 0 , 4/9 )
 11 months ago

morganKINGBest ResponseYou've already chosen the best response.0
were did 3x come from
 11 months ago

4kec4Best ResponseYou've already chosen the best response.0
@morganKING i am getting 1 for the limit of this one, but when i graph i am getting f(t)=3, as t approaches 0
 11 months ago

myininayaBest ResponseYou've already chosen the best response.1
Are you having trouble finding the derivative? That is the only scenario I can see here since it tells you to use lhospital.
 11 months ago

myininayaBest ResponseYou've already chosen the best response.1
let f(t)=t(1cos(t)) and g(t)=tsin(t) f(0)=0 and g(0)=0 since we have 0/0 we can use l'hopital rule (i think it is much easier to multiply the bottom by 1+sin(t) by whateves; it doesn't say to do that) Do limt>0 (f'/g') since we have f/g=0/0
 11 months ago

myininayaBest ResponseYou've already chosen the best response.1
Not for your problem you asked about.
 11 months ago

morganKINGBest ResponseYou've already chosen the best response.0
yeah the derivative confused me @myininaya but not sure
 11 months ago

morganKINGBest ResponseYou've already chosen the best response.0
aw k gona try again
 11 months ago

myininayaBest ResponseYou've already chosen the best response.1
let f(t)=t(1cos(t)) and g(t)=tsin(t) Recall this above f(t)=ttcos(t) f'(t)=(ttcos(t))'=(t)'(tcos(t))' Derivative of t is easy For finding the derivative of tcos(t) you need the product rule. g'(t) is a bit easier to find.
 11 months ago

morganKINGBest ResponseYou've already chosen the best response.0
ZZZ dont get this keep on getting 0/0
 11 months ago

myininayaBest ResponseYou've already chosen the best response.1
You should not getting 0/0 after differentiating three times.
 11 months ago
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