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UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
which one?
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
all of them @UnkleRhaukus just want to check if the answer is right or not
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.2
A and D are correct
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.2
\[ \lim_{x\to \pi ^}( \cot x) =\infty \]
 one year ago

Euler271 Group TitleBest ResponseYou've already chosen the best response.0
my bad thought it was tanx not cotx
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.2
All good except E
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
@.Sam. SO A and D are right what about b and c and e
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.2
\[ \lim_{x\to \left(\frac{\pi }{2}\right)^+} ( \tan x) =\infty\]
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
So @.Sam. which all have i done right
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.2
All good except for E
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
So how do we have to do e
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
@u0860867 i think you found \[\lim_{x\to\pi/2^}\tan x=\infty\] but the question is \[\lim_{x\to\pi/2^+}\tan x\]
 one year ago

Euler271 Group TitleBest ResponseYou've already chosen the best response.0
E asks is the limit approaching from the right of pi/2
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.2
Yeah exactly unkle, we got the vertical asymptote at 3pi/2, So as x approaches pi/2, with asymptote at 3pi/2 you will get infinity because its at the left side of the asymtotes
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
so i just ned to put a negative sign infront of my answer
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
thanks @.Sam. and @UnkleRhaukus , @Euler271
 one year ago
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