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In the integral \[\int\limits_{V}^{}\rho _{v}dV\] to determine the enclosed charge, can \[\rho _{v}dV\] be changed to \[\rho _{v} \] dot Ads??

Engineering
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is this across an x,y,z region?
this is in spherical coordinate system...
... that one has something like \(\rho~sin^2\) if memory serves

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Other answers:

\[\rho^2~sin(\phi)~ddd\]
yes, for us rho is R...
but would it be possible then to change the differential volume to area multiplied by the differential length? I was working through a test and it's been done here, but it's the first time that I'm seeing this being done...
im not up to snuff on sphericals enough to be certain
Oky, but thanks anyway.

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