BillyBobJoe
x = sqrt 4x + 12



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Diyadiya
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What do you want to find?

BillyBobJoe
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I want to solve the equation.

Diyadiya
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\[x=\sqrt{4x} + 12\] or \[x= \sqrt{4}x +12\]

Diyadiya
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is it the second one or first one?
Anyways, sqrt of 4 is 2

BillyBobJoe
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I ended up with 6 and 2 somehow.

Diyadiya
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try to isolate and find x

Diyadiya
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If its the second eqation then,
x=2x+12
2x+x=12
x=12
x=2x+12
2x+x=12
x=4