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ikoreanx3
Could anyone show me the steps on how to solve this problem? square root x^2+12x+3=-x
I got x=-1/4 is this right?
\[\sqrt{x^2+12x+3}=-x\]
\[\frac{ -b \pm \sqrt {b^2-4ac }}{ 2a }\]
but its radical expression though o:
first square both the sides
I dont understand that part but i know you plug the numbers into the formula. Sorry T: i'm confused.
squaring both sides will give you x^2+12x+3=x^2 12x=-3 x= -3/12=-1/4