anonymous
  • anonymous
Could anyone show me the steps on how to solve this problem? square root x^2+12x+3=-x
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
I got x=-1/4 is this right?
anonymous
  • anonymous
\[\sqrt{x^2+12x+3}=-x\]
anonymous
  • anonymous
\[\frac{ -b \pm \sqrt {b^2-4ac }}{ 2a }\]

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anonymous
  • anonymous
but its radical expression though o:
anonymous
  • anonymous
first square both the sides
anonymous
  • anonymous
I dont understand that part but i know you plug the numbers into the formula. Sorry T: i'm confused.
anonymous
  • anonymous
squaring both sides will give you x^2+12x+3=x^2 12x=-3 x= -3/12=-1/4

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