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ikoreanx3

  • 2 years ago

Could anyone show me the steps on how to solve this problem? square root x^2+12x+3=-x

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  1. ikoreanx3
    • 2 years ago
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    I got x=-1/4 is this right?

  2. ikoreanx3
    • 2 years ago
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    \[\sqrt{x^2+12x+3}=-x\]

  3. erica.d
    • 2 years ago
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    \[\frac{ -b \pm \sqrt {b^2-4ac }}{ 2a }\]

  4. ikoreanx3
    • 2 years ago
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    but its radical expression though o:

  5. erica.d
    • 2 years ago
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    first square both the sides

  6. ikoreanx3
    • 2 years ago
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    I dont understand that part but i know you plug the numbers into the formula. Sorry T: i'm confused.

  7. erica.d
    • 2 years ago
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    squaring both sides will give you x^2+12x+3=x^2 12x=-3 x= -3/12=-1/4

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