Christos
  • Christos
Derivatives, There is this problem that asks me to find the derivative of f(x)=2x^2 ONLY by making use of this formula: f'(x)=lim(h-->0)(f(x+h)-f(x))/h My Question is this: http://screencast.com/t/fdJEOQduGCj
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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AravindG
  • AravindG
Yep just use that formula
Christos
  • Christos
Check at my question
AravindG
  • AravindG
f(x+h)=? f(x)=?

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More answers

AravindG
  • AravindG
Can you write those?
anonymous
  • anonymous
?????? it is right?????? the derivative is 4x
Christos
  • Christos
f(x)= 2x^2 f(x=h)= 2(x+h)^2
AravindG
  • AravindG
*f(x+h)
AravindG
  • AravindG
f(x+h)= 2x^2 f(x=h)= 2(x+h)^2
Christos
  • Christos
But my approach (the one with the red letters) gives 0. And I didn't do any mistake
Christos
  • Christos
thats what I said @AravindG
Christos
  • Christos
ah yea +**
AravindG
  • AravindG
What is your problem ? You are getting correct answer 4x ?
Christos
  • Christos
No, look. The black letters is the solution manual. On the other hand the RED letters are my approach. The solution gives 4x. My solution gives 0. Both solutions doesn't have any mathematical mistake. ( and it's driving me crazy)
AravindG
  • AravindG
Why 0 ? You are told x=0 ?
Christos
  • Christos
lim (h--->0)
AravindG
  • AravindG
that will be 0+4x .I dont see 0 anywhere
AravindG
  • AravindG
0+4x=4x
Christos
  • Christos
Do you see this http://screencast.com/t/YqaRwsAr5b
Christos
  • Christos
@AravindG
AravindG
  • AravindG
so option 1 will be correct
Christos
  • Christos
buth both options doesn't have any mathematical mistakes. Agree?
AravindG
  • AravindG
tell me which options you are speaking of
Christos
  • Christos
the red
AravindG
  • AravindG
I see 4 options
AravindG
  • AravindG
Which do you mean by saying both ?
Christos
  • Christos
Wait. Let me write the whole thing here on Open Study , 1 sec
AravindG
  • AravindG
k
Christos
  • Christos
Forget it I got my mistake, jeez and phew
AravindG
  • AravindG
lol Great you figured it out yourself :)

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