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Derivatives, There is this problem that asks me to find the derivative of f(x)=2x^2 ONLY by making use of this formula: f'(x)=lim(h-->0)(f(x+h)-f(x))/h My Question is this: http://screencast.com/t/fdJEOQduGCj

Mathematics
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Yep just use that formula
Check at my question
f(x+h)=? f(x)=?

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Other answers:

Can you write those?
?????? it is right?????? the derivative is 4x
f(x)= 2x^2 f(x=h)= 2(x+h)^2
*f(x+h)
f(x+h)= 2x^2 f(x=h)= 2(x+h)^2
But my approach (the one with the red letters) gives 0. And I didn't do any mistake
thats what I said @AravindG
ah yea +**
What is your problem ? You are getting correct answer 4x ?
No, look. The black letters is the solution manual. On the other hand the RED letters are my approach. The solution gives 4x. My solution gives 0. Both solutions doesn't have any mathematical mistake. ( and it's driving me crazy)
Why 0 ? You are told x=0 ?
lim (h--->0)
that will be 0+4x .I dont see 0 anywhere
0+4x=4x
Do you see this http://screencast.com/t/YqaRwsAr5b
so option 1 will be correct
buth both options doesn't have any mathematical mistakes. Agree?
tell me which options you are speaking of
the red
I see 4 options
Which do you mean by saying both ?
Wait. Let me write the whole thing here on Open Study , 1 sec
k
Forget it I got my mistake, jeez and phew
lol Great you figured it out yourself :)

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