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Show that there is no integer
a such that a^2−3a−19 is divisible by 289.
 11 months ago
 11 months ago
Show that there is no integer a such that a^2−3a−19 is divisible by 289.
 11 months ago
 11 months ago

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AravindGBest ResponseYou've already chosen the best response.0
Are you sure your question right?
 11 months ago

goformit100Best ResponseYou've already chosen the best response.0
Ya I typed the question Now correctly, Just Accept Answer
 11 months ago

AravindGBest ResponseYou've already chosen the best response.0
ok How much have you progressed in this question?
 11 months ago

AravindGBest ResponseYou've already chosen the best response.0
we cant JUST give YOU the answer
 11 months ago

deathgrowlBest ResponseYou've already chosen the best response.0
did you mean the factor is not integer?
 11 months ago

goformit100Best ResponseYou've already chosen the best response.0
Sir I am unable to Visulize this Question
 11 months ago

NotTimBest ResponseYou've already chosen the best response.0
ah, if only i could help.
 11 months ago

NotTimBest ResponseYou've already chosen the best response.0
sorry, what's an integer?
 11 months ago

MachidaBest ResponseYou've already chosen the best response.1
dw:1367902685272:dw
 11 months ago

NotTimBest ResponseYou've already chosen the best response.0
uh. how'd you get that?
 11 months ago

MachidaBest ResponseYou've already chosen the best response.1
dw:1367902803183:dw
 11 months ago

goformit100Best ResponseYou've already chosen the best response.0
Thank you Madam and Sir
 11 months ago

MachidaBest ResponseYou've already chosen the best response.1
then a^23a+(19289k)=0 Do you know that Ax^2+Bx+C=0? I use this B^2 4AC A=1, B=3, C=(19289k) So its be (3)^24.(1).((19289k)
 11 months ago

MachidaBest ResponseYou've already chosen the best response.1
9+76+1156k 85+1156k then I use 17(5+68k)
 11 months ago

MachidaBest ResponseYou've already chosen the best response.1
5+68k must be have 17 factor for some perfect square, 5+68k=17n 5=17n68k 5/17=(n4k) Found that its not integer, because there are 5/17.. even right side is integer. CMIWW @goformit100
 11 months ago
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