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IgorL

  • one year ago

How can I solve integral of 2sin(t/2)dt?

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  1. AravindG
    • one year ago
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    put u=t/2 du=1/2 dt the integral becomes integral 2 sin u 1/2 du = integral sin u du

  2. EulersEquation
    • one year ago
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    Are you looking for \[\int\limits_{} 2\sin(t/2) dt\]?

  3. IgorL
    • one year ago
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    yes

  4. EulersEquation
    • one year ago
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    This one is easy, really. Can you figure out the antiderivative? The antiderivative of sin is what? And the antiderivative then of t/2 is what? You would be using the chain rule to differentiate to get this function.

  5. IgorL
    • one year ago
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    I just solved, and it is -4cos(t/2)+c. But I used u substitution.

  6. AravindG
    • one year ago
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    Where did 4 come from ?

  7. IgorL
    • one year ago
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    when ask my question before, you forget to multiply du by 2. I think you divided by 2 instead of multiply.

  8. AravindG
    • one year ago
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    ya u r right ..sorry for that

  9. IgorL
    • one year ago
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    ok :)

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