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@amistre64 @Callisto @phi
Did you graph them and found the solution region?
No, How would I do that?
use graph paper graph the lines y=x-5 and y=-x-4
find the region below or on the line y=x-5 and above or on the line y=-x-4
you could also use a graphing calculator
Here is one : http://my.hrw.com/math06_07/nsmedia/tools/Graph_Calculator/graphCalc.html
I'm in a library, so I don't have graphing paper, and I have no clue how to use a graphing calculator. :/
its easy just plugin the quations in boxes y1 and y2
Okay. I'll try it right now;
or go to https://www.desmos.com/calculator and type in the two equations (copy and paste works too)
How do I make a less than or equal too sign on the graphing calculator?
you don't need to, just graph the line and remember you are looking at the region less than or equal to it
In my calculator click on the square having equal to after the y1 or y2
I'm so confused > . <
in desmos, enter the less than sign then the equals sign <= or >=
Okay, I'm gonna use desmos then.
I did it. What next?
you typed in both your equations?
look at where your four points are
see which one satisfies both inequalities
0,5 and -4,5
i woulda just plugged in the 4 points to see what made true results
(-5, 2) is 2 <= -5 - 5 true? is 2 >= --5 - 4 true? (5, -2) is -2 <= 5 - 5 true? is -2 >= -5 - 4 true? (-5, -2) is -2 <= -5 - 5 true? is -2 >= --5 - 4 true? (5, 2) is 2 <= 5 - 5 true? is 2 >= -5 - 4 true?
Oh, okay! @amistre64 I'll try that,
it is nice to know that other stuff, but it takes way to much time when taking a test.
It's -5, -2, right?
(-5, -2) -2 <= 0 true -2 >= 1 false not that one
well, -10 up top, but still false :)
So, it's -5, something right?
dunno, lets try another one (5, -2) -2 <= 5 - 5 -2 <= 0 true -2 >= -5 - 4 -2 >= -9 true that fits nicely
Awesome. Thanks :)