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InsanelyChaotic

  • 2 years ago

HOW ON EARTH DO I DO THIS???

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  1. AravindG
    • 2 years ago
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    Ofcourse you cant do it on MOON

  2. InsanelyChaotic
    • 2 years ago
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  3. InsanelyChaotic
    • 2 years ago
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    @AravindG

  4. AravindG
    • 2 years ago
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    Are all these 4 pics referring to same question?

  5. InsanelyChaotic
    • 2 years ago
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    yes

  6. AravindG
    • 2 years ago
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    I see 5 questions .Which one do you have doubt on ?

  7. InsanelyChaotic
    • 2 years ago
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    all of them. they literally make no sense. this whole time i thought it was one problem. it wan't set up correctly in the word doc format

  8. AravindG
    • 2 years ago
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    1. root(27)=root(3*9)

  9. AravindG
    • 2 years ago
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    root(3*9)=root(3) *root (9)

  10. AravindG
    • 2 years ago
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    I hope you can do it after that

  11. InsanelyChaotic
    • 2 years ago
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    should i plug the roots into the calc?

  12. InsanelyChaotic
    • 2 years ago
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    @AravindG

  13. InsanelyChaotic
    • 2 years ago
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    please!!!!!!!!!!!!:((((((((((((((((((((((((((

  14. AravindG
    • 2 years ago
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    nope for example \[\sqrt{2}x-\sqrt{8} \times 3=\sqrt{2}x-\sqrt{4 \times 2} \times 3 =\sqrt{2}x-2\sqrt{2} \times 3\] \[=\sqrt{2} \times (x-6)\]

  15. AravindG
    • 2 years ago
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    This is how to do these type of problems

  16. InsanelyChaotic
    • 2 years ago
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    i just need help this makes no sense

  17. InsanelyChaotic
    • 2 years ago
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    @Best_Mathematician

  18. InsanelyChaotic
    • 2 years ago
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    @Aperogalics

  19. InsanelyChaotic
    • 2 years ago
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    @Chooch146

  20. Aperogalics
    • 2 years ago
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    @InsanelyChaotic how can i help u ????????

  21. InsanelyChaotic
    • 2 years ago
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    With the problem listed above please. it makes no sense and i just want to cry.

  22. Aperogalics
    • 2 years ago
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    don't cry first of all :) let us solve

  23. Aperogalics
    • 2 years ago
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    first question |dw:1367947608900:dw| in such type of questions we have to take common now second part can be factorise so |dw:1367947718184:dw| but in square root if a no. comes twice that is a pair of two then it comes out and only one term remains i.e.|dw:1367947798491:dw| so back to question |dw:1367947833712:dw| got it if yes then tell me i will proceed to second :)

  24. InsanelyChaotic
    • 2 years ago
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    so far so good!!:)))))))))

  25. Aperogalics
    • 2 years ago
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    ok so let solve second one....... r u ready ??????

  26. InsanelyChaotic
    • 2 years ago
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    |dw:1367951666372:dw|

  27. Aperogalics
    • 2 years ago
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    ok 3*3= is a pair so we can take it out it's a property of square roots if it is cubic then a pair of three .....etc e.g.|dw:1367948458812:dw|

  28. Aperogalics
    • 2 years ago
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    if u got redy then mention me :)

  29. InsanelyChaotic
    • 2 years ago
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    perf:))))

  30. Aperogalics
    • 2 years ago
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    so should we proceed??????

  31. Aperogalics
    • 2 years ago
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    @InsanelyChaotic ?????????

  32. InsanelyChaotic
    • 2 years ago
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    yes please!

  33. InsanelyChaotic
    • 2 years ago
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    sorry i was taking notes on your genuis work

  34. Aperogalics
    • 2 years ago
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    k :) second question |dw:1367949085845:dw| just type so not to switch other window :)

  35. InsanelyChaotic
    • 2 years ago
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    |dw:1367952732165:dw|

  36. Aperogalics
    • 2 years ago
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    \[3\sqrt{4xy}\]

  37. Aperogalics
    • 2 years ago
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    now |dw:1367949356565:dw|

  38. Aperogalics
    • 2 years ago
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    try to do this :)

  39. InsanelyChaotic
    • 2 years ago
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    dont know

  40. InsanelyChaotic
    • 2 years ago
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    all of which is makes me is want to kill myelf

  41. Aperogalics
    • 2 years ago
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    no it happens to me also when i start these square root and all this but now i just do it :)

  42. Aperogalics
    • 2 years ago
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    so better not to kill urself :)

  43. InsanelyChaotic
    • 2 years ago
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    thank you...tempting though

  44. Aperogalics
    • 2 years ago
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    k first multiply the terms outside the square root and tell the answer :)

  45. InsanelyChaotic
    • 2 years ago
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    okay bb

  46. InsanelyChaotic
    • 2 years ago
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    ab^2

  47. Aperogalics
    • 2 years ago
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    a&b are not the terms :)

  48. InsanelyChaotic
    • 2 years ago
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    oops thats awkward

  49. InsanelyChaotic
    • 2 years ago
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    you probably think i'm stupid

  50. Aperogalics
    • 2 years ago
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    no i think everything is going messed up in ur mind and u r trying to solve by heart otherwise either u will leave it or you tore the paper ;)

  51. InsanelyChaotic
    • 2 years ago
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    awww that was beautiful

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