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## anonymous 3 years ago I GIVE MEDALS Find the fifth roots of 243(cos 300° + i sin 300°).

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1. anonymous

@amistre64 :) can you help with another couple ?

2. AravindG

nice name :)

3. anonymous

@AravindG thanks ... can you help ?

4. anonymous

450^2

5. anonymous

@josie_2015 can you give the work with it ?

6. amistre64

the 5th roots are essentially adding 2pi/5 to what you have

7. amistre64

243(cos ((5/3+2n/5) pi) + i sin((5/3+2n/5)pi ) ) n = 0 to 4

8. anonymous

so thats the final answer ?

9. amistre64

im not sure what a "final answer" should be formated as; but yes ....

10. amistre64

5th roots are just |dw:1367951499404:dw|

11. amistre64

so start where you are at; 5pi/3 and add on each root

12. amistre64

72 degrees might be easier to read tho

13. amistre64

$\frac{x}{x-5}$ $\frac{x+0}{x-5}$ $\frac{x+(5-5)}{x-5}$ $\frac{x-5}{x-5}+\frac{5}{x-5}$ $1+\frac{5}{x-5}$

14. anonymous

would my response be correct ?

15. anonymous

confused lol

16. amistre64

this is approaching -inf, yes

17. anonymous

thank you so much one more?

18. amistre64

we could say that the slope of 1+5/(x-5) = -5/(x-5)^2 is always negative as x approaches 5 from the left ... but sure, one more

19. amistre64

well, since the picture shows the distance along the y axis to be bigger than the x axis .. we want the under ys to be bigger than the under xs by default. that narrow it to 2 options

20. amistre64

and since the center of the moon is 1000 further than its surface, that should make the correct choice rather obvious

21. anonymous

option D?

22. anonymous

@amistre64

23. amistre64

option D is not correct, since the under y is smaller than the under x

24. anonymous

so then my last educated guess is C @amistre64

25. amistre64

i would deduce that you need better education then :) C still has the under y smaller than the under x, AND it is missing the 1000 extra stuff for the radius ...

26. amistre64

assume for a moment we have this setup:|dw:1367953733151:dw| in order for this to make any sense:$\frac{x^2}{n^2}+\frac{y^2}{m^2}=1$when x=0, we have y=2$\frac{0^2}{n^2}+\frac{2^2}{m^2}=1~:~m=2$ when y=0, we have x=1$\frac{1^2}{n^2}+\frac{0^2}{2^2}=1~:~n=1$ therefore our setup has to be:$\frac{x^2}{1^2}+\frac{y^2}{2^2}=1$ the part under the y has to be greater than the part under the x

27. amistre64

in your case: 953 is bigger than 466, but thats not accounting for the extra 1000 radius, sooo.... y x 1953 is bigger than 1466

28. anonymous

WOW THANKS SO MUCH I SEE NOW !

29. amistre64

good luck ... ;)

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