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anonymous
 3 years ago
I GIVE MEDALS
Find the fifth roots of 243(cos 300° + i sin 300°).
anonymous
 3 years ago
I GIVE MEDALS Find the fifth roots of 243(cos 300° + i sin 300°).

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@amistre64 :) can you help with another couple ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@AravindG thanks ... can you help ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@josie_2015 can you give the work with it ?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1the 5th roots are essentially adding 2pi/5 to what you have

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1243(cos ((5/3+2n/5) pi) + i sin((5/3+2n/5)pi ) ) n = 0 to 4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so thats the final answer ?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1im not sure what a "final answer" should be formated as; but yes ....

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.15th roots are just dw:1367951499404:dw

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1so start where you are at; 5pi/3 and add on each root

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.172 degrees might be easier to read tho

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{x}{x5}\] \[\frac{x+0}{x5}\] \[\frac{x+(55)}{x5}\] \[\frac{x5}{x5}+\frac{5}{x5}\] \[1+\frac{5}{x5}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0would my response be correct ?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1this is approaching inf, yes

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you so much one more?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1we could say that the slope of 1+5/(x5) = 5/(x5)^2 is always negative as x approaches 5 from the left ... but sure, one more

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1well, since the picture shows the distance along the y axis to be bigger than the x axis .. we want the under ys to be bigger than the under xs by default. that narrow it to 2 options

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1and since the center of the moon is 1000 further than its surface, that should make the correct choice rather obvious

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1option D is not correct, since the under y is smaller than the under x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so then my last educated guess is C @amistre64

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1i would deduce that you need better education then :) C still has the under y smaller than the under x, AND it is missing the 1000 extra stuff for the radius ...

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1assume for a moment we have this setup:dw:1367953733151:dw in order for this to make any sense:\[\frac{x^2}{n^2}+\frac{y^2}{m^2}=1\]when x=0, we have y=2\[\frac{0^2}{n^2}+\frac{2^2}{m^2}=1~:~m=2\] when y=0, we have x=1\[\frac{1^2}{n^2}+\frac{0^2}{2^2}=1~:~n=1\] therefore our setup has to be:\[\frac{x^2}{1^2}+\frac{y^2}{2^2}=1\] the part under the y has to be greater than the part under the x

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1in your case: 953 is bigger than 466, but thats not accounting for the extra 1000 radius, sooo.... y x 1953 is bigger than 1466

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0WOW THANKS SO MUCH I SEE NOW !
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