A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Needamedal
 one year ago
Best ResponseYou've already chosen the best response.0@amistre64 :) can you help with another couple ?

Needamedal
 one year ago
Best ResponseYou've already chosen the best response.0@AravindG thanks ... can you help ?

Needamedal
 one year ago
Best ResponseYou've already chosen the best response.0@josie_2015 can you give the work with it ?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1the 5th roots are essentially adding 2pi/5 to what you have

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1243(cos ((5/3+2n/5) pi) + i sin((5/3+2n/5)pi ) ) n = 0 to 4

Needamedal
 one year ago
Best ResponseYou've already chosen the best response.0so thats the final answer ?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1im not sure what a "final answer" should be formated as; but yes ....

amistre64
 one year ago
Best ResponseYou've already chosen the best response.15th roots are just dw:1367951499404:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1so start where you are at; 5pi/3 and add on each root

amistre64
 one year ago
Best ResponseYou've already chosen the best response.172 degrees might be easier to read tho

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{x}{x5}\] \[\frac{x+0}{x5}\] \[\frac{x+(55)}{x5}\] \[\frac{x5}{x5}+\frac{5}{x5}\] \[1+\frac{5}{x5}\]

Needamedal
 one year ago
Best ResponseYou've already chosen the best response.0would my response be correct ?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1this is approaching inf, yes

Needamedal
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much one more?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1we could say that the slope of 1+5/(x5) = 5/(x5)^2 is always negative as x approaches 5 from the left ... but sure, one more

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1well, since the picture shows the distance along the y axis to be bigger than the x axis .. we want the under ys to be bigger than the under xs by default. that narrow it to 2 options

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1and since the center of the moon is 1000 further than its surface, that should make the correct choice rather obvious

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1option D is not correct, since the under y is smaller than the under x

Needamedal
 one year ago
Best ResponseYou've already chosen the best response.0so then my last educated guess is C @amistre64

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1i would deduce that you need better education then :) C still has the under y smaller than the under x, AND it is missing the 1000 extra stuff for the radius ...

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1assume for a moment we have this setup:dw:1367953733151:dw in order for this to make any sense:\[\frac{x^2}{n^2}+\frac{y^2}{m^2}=1\]when x=0, we have y=2\[\frac{0^2}{n^2}+\frac{2^2}{m^2}=1~:~m=2\] when y=0, we have x=1\[\frac{1^2}{n^2}+\frac{0^2}{2^2}=1~:~n=1\] therefore our setup has to be:\[\frac{x^2}{1^2}+\frac{y^2}{2^2}=1\] the part under the y has to be greater than the part under the x

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1in your case: 953 is bigger than 466, but thats not accounting for the extra 1000 radius, sooo.... y x 1953 is bigger than 1466

Needamedal
 one year ago
Best ResponseYou've already chosen the best response.0WOW THANKS SO MUCH I SEE NOW !
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.