I GIVE MEDALS Find the fifth roots of 243(cos 300° + i sin 300°).

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I GIVE MEDALS Find the fifth roots of 243(cos 300° + i sin 300°).

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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@amistre64 :) can you help with another couple ?
nice name :)
@AravindG thanks ... can you help ?

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Other answers:

450^2
@josie_2015 can you give the work with it ?
the 5th roots are essentially adding 2pi/5 to what you have
243(cos ((5/3+2n/5) pi) + i sin((5/3+2n/5)pi ) ) n = 0 to 4
so thats the final answer ?
im not sure what a "final answer" should be formated as; but yes ....
5th roots are just |dw:1367951499404:dw|
so start where you are at; 5pi/3 and add on each root
72 degrees might be easier to read tho
\[\frac{x}{x-5}\] \[\frac{x+0}{x-5}\] \[\frac{x+(5-5)}{x-5}\] \[\frac{x-5}{x-5}+\frac{5}{x-5}\] \[1+\frac{5}{x-5}\]
would my response be correct ?
confused lol
this is approaching -inf, yes
thank you so much one more?
we could say that the slope of 1+5/(x-5) = -5/(x-5)^2 is always negative as x approaches 5 from the left ... but sure, one more
well, since the picture shows the distance along the y axis to be bigger than the x axis .. we want the under ys to be bigger than the under xs by default. that narrow it to 2 options
and since the center of the moon is 1000 further than its surface, that should make the correct choice rather obvious
option D?
option D is not correct, since the under y is smaller than the under x
so then my last educated guess is C @amistre64
i would deduce that you need better education then :) C still has the under y smaller than the under x, AND it is missing the 1000 extra stuff for the radius ...
assume for a moment we have this setup:|dw:1367953733151:dw| in order for this to make any sense:\[\frac{x^2}{n^2}+\frac{y^2}{m^2}=1\]when x=0, we have y=2\[\frac{0^2}{n^2}+\frac{2^2}{m^2}=1~:~m=2\] when y=0, we have x=1\[\frac{1^2}{n^2}+\frac{0^2}{2^2}=1~:~n=1\] therefore our setup has to be:\[\frac{x^2}{1^2}+\frac{y^2}{2^2}=1\] the part under the y has to be greater than the part under the x
in your case: 953 is bigger than 466, but thats not accounting for the extra 1000 radius, sooo.... y x 1953 is bigger than 1466
WOW THANKS SO MUCH I SEE NOW !
good luck ... ;)

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