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I GIVE MEDALS
Find the fifth roots of 243(cos 300° + i sin 300°).
 11 months ago
 11 months ago
I GIVE MEDALS Find the fifth roots of 243(cos 300° + i sin 300°).
 11 months ago
 11 months ago

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NeedamedalBest ResponseYou've already chosen the best response.0
@amistre64 :) can you help with another couple ?
 11 months ago

NeedamedalBest ResponseYou've already chosen the best response.0
@AravindG thanks ... can you help ?
 11 months ago

NeedamedalBest ResponseYou've already chosen the best response.0
@josie_2015 can you give the work with it ?
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
the 5th roots are essentially adding 2pi/5 to what you have
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
243(cos ((5/3+2n/5) pi) + i sin((5/3+2n/5)pi ) ) n = 0 to 4
 11 months ago

NeedamedalBest ResponseYou've already chosen the best response.0
so thats the final answer ?
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
im not sure what a "final answer" should be formated as; but yes ....
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
5th roots are just dw:1367951499404:dw
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
so start where you are at; 5pi/3 and add on each root
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
72 degrees might be easier to read tho
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
\[\frac{x}{x5}\] \[\frac{x+0}{x5}\] \[\frac{x+(55)}{x5}\] \[\frac{x5}{x5}+\frac{5}{x5}\] \[1+\frac{5}{x5}\]
 11 months ago

NeedamedalBest ResponseYou've already chosen the best response.0
would my response be correct ?
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
this is approaching inf, yes
 11 months ago

NeedamedalBest ResponseYou've already chosen the best response.0
thank you so much one more?
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
we could say that the slope of 1+5/(x5) = 5/(x5)^2 is always negative as x approaches 5 from the left ... but sure, one more
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
well, since the picture shows the distance along the y axis to be bigger than the x axis .. we want the under ys to be bigger than the under xs by default. that narrow it to 2 options
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
and since the center of the moon is 1000 further than its surface, that should make the correct choice rather obvious
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
option D is not correct, since the under y is smaller than the under x
 11 months ago

NeedamedalBest ResponseYou've already chosen the best response.0
so then my last educated guess is C @amistre64
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
i would deduce that you need better education then :) C still has the under y smaller than the under x, AND it is missing the 1000 extra stuff for the radius ...
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
assume for a moment we have this setup:dw:1367953733151:dw in order for this to make any sense:\[\frac{x^2}{n^2}+\frac{y^2}{m^2}=1\]when x=0, we have y=2\[\frac{0^2}{n^2}+\frac{2^2}{m^2}=1~:~m=2\] when y=0, we have x=1\[\frac{1^2}{n^2}+\frac{0^2}{2^2}=1~:~n=1\] therefore our setup has to be:\[\frac{x^2}{1^2}+\frac{y^2}{2^2}=1\] the part under the y has to be greater than the part under the x
 11 months ago

amistre64Best ResponseYou've already chosen the best response.1
in your case: 953 is bigger than 466, but thats not accounting for the extra 1000 radius, sooo.... y x 1953 is bigger than 1466
 11 months ago

NeedamedalBest ResponseYou've already chosen the best response.0
WOW THANKS SO MUCH I SEE NOW !
 11 months ago
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