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Needamedal

  • 2 years ago

I GIVE MEDALS Find the fifth roots of 243(cos 300° + i sin 300°).

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  1. Needamedal
    • 2 years ago
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    @amistre64 :) can you help with another couple ?

  2. AravindG
    • 2 years ago
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    nice name :)

  3. Needamedal
    • 2 years ago
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    @AravindG thanks ... can you help ?

  4. josie_2015
    • 2 years ago
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    450^2

  5. Needamedal
    • 2 years ago
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    @josie_2015 can you give the work with it ?

  6. amistre64
    • 2 years ago
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    the 5th roots are essentially adding 2pi/5 to what you have

  7. amistre64
    • 2 years ago
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    243(cos ((5/3+2n/5) pi) + i sin((5/3+2n/5)pi ) ) n = 0 to 4

  8. Needamedal
    • 2 years ago
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    so thats the final answer ?

  9. amistre64
    • 2 years ago
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    im not sure what a "final answer" should be formated as; but yes ....

  10. amistre64
    • 2 years ago
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    5th roots are just |dw:1367951499404:dw|

  11. amistre64
    • 2 years ago
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    so start where you are at; 5pi/3 and add on each root

  12. amistre64
    • 2 years ago
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    72 degrees might be easier to read tho

  13. amistre64
    • 2 years ago
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    \[\frac{x}{x-5}\] \[\frac{x+0}{x-5}\] \[\frac{x+(5-5)}{x-5}\] \[\frac{x-5}{x-5}+\frac{5}{x-5}\] \[1+\frac{5}{x-5}\]

  14. Needamedal
    • 2 years ago
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    would my response be correct ?

  15. Needamedal
    • 2 years ago
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    confused lol

  16. amistre64
    • 2 years ago
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    this is approaching -inf, yes

  17. Needamedal
    • 2 years ago
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    thank you so much one more?

  18. amistre64
    • 2 years ago
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    we could say that the slope of 1+5/(x-5) = -5/(x-5)^2 is always negative as x approaches 5 from the left ... but sure, one more

  19. amistre64
    • 2 years ago
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    well, since the picture shows the distance along the y axis to be bigger than the x axis .. we want the under ys to be bigger than the under xs by default. that narrow it to 2 options

  20. amistre64
    • 2 years ago
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    and since the center of the moon is 1000 further than its surface, that should make the correct choice rather obvious

  21. Needamedal
    • 2 years ago
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    option D?

  22. Needamedal
    • 2 years ago
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    @amistre64

  23. amistre64
    • 2 years ago
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    option D is not correct, since the under y is smaller than the under x

  24. Needamedal
    • 2 years ago
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    so then my last educated guess is C @amistre64

  25. amistre64
    • 2 years ago
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    i would deduce that you need better education then :) C still has the under y smaller than the under x, AND it is missing the 1000 extra stuff for the radius ...

  26. amistre64
    • 2 years ago
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    assume for a moment we have this setup:|dw:1367953733151:dw| in order for this to make any sense:\[\frac{x^2}{n^2}+\frac{y^2}{m^2}=1\]when x=0, we have y=2\[\frac{0^2}{n^2}+\frac{2^2}{m^2}=1~:~m=2\] when y=0, we have x=1\[\frac{1^2}{n^2}+\frac{0^2}{2^2}=1~:~n=1\] therefore our setup has to be:\[\frac{x^2}{1^2}+\frac{y^2}{2^2}=1\] the part under the y has to be greater than the part under the x

  27. amistre64
    • 2 years ago
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    in your case: 953 is bigger than 466, but thats not accounting for the extra 1000 radius, sooo.... y x 1953 is bigger than 1466

  28. Needamedal
    • 2 years ago
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    WOW THANKS SO MUCH I SEE NOW !

  29. amistre64
    • 2 years ago
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    good luck ... ;)

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