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Needamedal
Group Title
I GIVE MEDALS
Find the fifth roots of 243(cos 300° + i sin 300°).
 one year ago
 one year ago
Needamedal Group Title
I GIVE MEDALS Find the fifth roots of 243(cos 300° + i sin 300°).
 one year ago
 one year ago

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Needamedal Group TitleBest ResponseYou've already chosen the best response.0
@amistre64 :) can you help with another couple ?
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
nice name :)
 one year ago

Needamedal Group TitleBest ResponseYou've already chosen the best response.0
@AravindG thanks ... can you help ?
 one year ago

Needamedal Group TitleBest ResponseYou've already chosen the best response.0
@josie_2015 can you give the work with it ?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
the 5th roots are essentially adding 2pi/5 to what you have
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
243(cos ((5/3+2n/5) pi) + i sin((5/3+2n/5)pi ) ) n = 0 to 4
 one year ago

Needamedal Group TitleBest ResponseYou've already chosen the best response.0
so thats the final answer ?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
im not sure what a "final answer" should be formated as; but yes ....
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
5th roots are just dw:1367951499404:dw
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
so start where you are at; 5pi/3 and add on each root
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
72 degrees might be easier to read tho
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{x}{x5}\] \[\frac{x+0}{x5}\] \[\frac{x+(55)}{x5}\] \[\frac{x5}{x5}+\frac{5}{x5}\] \[1+\frac{5}{x5}\]
 one year ago

Needamedal Group TitleBest ResponseYou've already chosen the best response.0
would my response be correct ?
 one year ago

Needamedal Group TitleBest ResponseYou've already chosen the best response.0
confused lol
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
this is approaching inf, yes
 one year ago

Needamedal Group TitleBest ResponseYou've already chosen the best response.0
thank you so much one more?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
we could say that the slope of 1+5/(x5) = 5/(x5)^2 is always negative as x approaches 5 from the left ... but sure, one more
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
well, since the picture shows the distance along the y axis to be bigger than the x axis .. we want the under ys to be bigger than the under xs by default. that narrow it to 2 options
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
and since the center of the moon is 1000 further than its surface, that should make the correct choice rather obvious
 one year ago

Needamedal Group TitleBest ResponseYou've already chosen the best response.0
option D?
 one year ago

Needamedal Group TitleBest ResponseYou've already chosen the best response.0
@amistre64
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
option D is not correct, since the under y is smaller than the under x
 one year ago

Needamedal Group TitleBest ResponseYou've already chosen the best response.0
so then my last educated guess is C @amistre64
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i would deduce that you need better education then :) C still has the under y smaller than the under x, AND it is missing the 1000 extra stuff for the radius ...
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
assume for a moment we have this setup:dw:1367953733151:dw in order for this to make any sense:\[\frac{x^2}{n^2}+\frac{y^2}{m^2}=1\]when x=0, we have y=2\[\frac{0^2}{n^2}+\frac{2^2}{m^2}=1~:~m=2\] when y=0, we have x=1\[\frac{1^2}{n^2}+\frac{0^2}{2^2}=1~:~n=1\] therefore our setup has to be:\[\frac{x^2}{1^2}+\frac{y^2}{2^2}=1\] the part under the y has to be greater than the part under the x
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
in your case: 953 is bigger than 466, but thats not accounting for the extra 1000 radius, sooo.... y x 1953 is bigger than 1466
 one year ago

Needamedal Group TitleBest ResponseYou've already chosen the best response.0
WOW THANKS SO MUCH I SEE NOW !
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
good luck ... ;)
 one year ago
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