anonymous
  • anonymous
I GIVE MEDALS Find the fifth roots of 243(cos 300° + i sin 300°).
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@amistre64 :) can you help with another couple ?
AravindG
  • AravindG
nice name :)
anonymous
  • anonymous
@AravindG thanks ... can you help ?

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More answers

anonymous
  • anonymous
450^2
anonymous
  • anonymous
@josie_2015 can you give the work with it ?
amistre64
  • amistre64
the 5th roots are essentially adding 2pi/5 to what you have
amistre64
  • amistre64
243(cos ((5/3+2n/5) pi) + i sin((5/3+2n/5)pi ) ) n = 0 to 4
anonymous
  • anonymous
so thats the final answer ?
amistre64
  • amistre64
im not sure what a "final answer" should be formated as; but yes ....
amistre64
  • amistre64
5th roots are just |dw:1367951499404:dw|
amistre64
  • amistre64
so start where you are at; 5pi/3 and add on each root
amistre64
  • amistre64
72 degrees might be easier to read tho
amistre64
  • amistre64
\[\frac{x}{x-5}\] \[\frac{x+0}{x-5}\] \[\frac{x+(5-5)}{x-5}\] \[\frac{x-5}{x-5}+\frac{5}{x-5}\] \[1+\frac{5}{x-5}\]
anonymous
  • anonymous
would my response be correct ?
anonymous
  • anonymous
confused lol
amistre64
  • amistre64
this is approaching -inf, yes
anonymous
  • anonymous
thank you so much one more?
amistre64
  • amistre64
we could say that the slope of 1+5/(x-5) = -5/(x-5)^2 is always negative as x approaches 5 from the left ... but sure, one more
amistre64
  • amistre64
well, since the picture shows the distance along the y axis to be bigger than the x axis .. we want the under ys to be bigger than the under xs by default. that narrow it to 2 options
amistre64
  • amistre64
and since the center of the moon is 1000 further than its surface, that should make the correct choice rather obvious
anonymous
  • anonymous
option D?
anonymous
  • anonymous
@amistre64
amistre64
  • amistre64
option D is not correct, since the under y is smaller than the under x
anonymous
  • anonymous
so then my last educated guess is C @amistre64
amistre64
  • amistre64
i would deduce that you need better education then :) C still has the under y smaller than the under x, AND it is missing the 1000 extra stuff for the radius ...
amistre64
  • amistre64
assume for a moment we have this setup:|dw:1367953733151:dw| in order for this to make any sense:\[\frac{x^2}{n^2}+\frac{y^2}{m^2}=1\]when x=0, we have y=2\[\frac{0^2}{n^2}+\frac{2^2}{m^2}=1~:~m=2\] when y=0, we have x=1\[\frac{1^2}{n^2}+\frac{0^2}{2^2}=1~:~n=1\] therefore our setup has to be:\[\frac{x^2}{1^2}+\frac{y^2}{2^2}=1\] the part under the y has to be greater than the part under the x
amistre64
  • amistre64
in your case: 953 is bigger than 466, but thats not accounting for the extra 1000 radius, sooo.... y x 1953 is bigger than 1466
anonymous
  • anonymous
WOW THANKS SO MUCH I SEE NOW !
amistre64
  • amistre64
good luck ... ;)

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