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modphysnoob
 one year ago
Best ResponseYou've already chosen the best response.0what's your question , sailor?

liliy
 one year ago
Best ResponseYou've already chosen the best response.0okay: i need to use derivative to verify that : p(x,t) = (1/(Sqrt[4 Pi t])) Exp[ x^2/(4 t) is the solution of the diffusion equation dp/dt= d^2p/dx^2

liliy
 one year ago
Best ResponseYou've already chosen the best response.0i got the value for dp/dt with the function :pt = D[(1./(Sqrt[4 Pi t])) Exp[ x^2/(4 t)], t]

liliy
 one year ago
Best ResponseYou've already chosen the best response.0but my second derivative of dx gives me 0.

liliy
 one year ago
Best ResponseYou've already chosen the best response.0dx = D[(1./(Sqrt[4 Pi t])) Exp[ x^2/(4 t)], {x, 2}] is there soemthign wrong with my equation?

modphysnoob
 one year ago
Best ResponseYou've already chosen the best response.0so are you trying to solve differential equation or take second derivative?

modphysnoob
 one year ago
Best ResponseYou've already chosen the best response.0second derviative goes like this D[ Type function here ,{x,2}]

modphysnoob
 one year ago
Best ResponseYou've already chosen the best response.0D[(1./(Sqrt[4 Pi t])) * Exp[ x^2/(4 t)], {x, 2}]

modphysnoob
 one year ago
Best ResponseYou've already chosen the best response.0./ is not used in mathematica, it is matlab notation

liliy
 one year ago
Best ResponseYou've already chosen the best response.0./ i was just trying to make the whole thing into a number so i tried to multiple (dividde) by 1. lol
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