Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

modphysnoobBest ResponseYou've already chosen the best response.0
what's your question , sailor?
 11 months ago

liliyBest ResponseYou've already chosen the best response.0
okay: i need to use derivative to verify that : p(x,t) = (1/(Sqrt[4 Pi t])) Exp[ x^2/(4 t) is the solution of the diffusion equation dp/dt= d^2p/dx^2
 11 months ago

liliyBest ResponseYou've already chosen the best response.0
i got the value for dp/dt with the function :pt = D[(1./(Sqrt[4 Pi t])) Exp[ x^2/(4 t)], t]
 11 months ago

liliyBest ResponseYou've already chosen the best response.0
but my second derivative of dx gives me 0.
 11 months ago

liliyBest ResponseYou've already chosen the best response.0
dx = D[(1./(Sqrt[4 Pi t])) Exp[ x^2/(4 t)], {x, 2}] is there soemthign wrong with my equation?
 11 months ago

modphysnoobBest ResponseYou've already chosen the best response.0
so are you trying to solve differential equation or take second derivative?
 11 months ago

modphysnoobBest ResponseYou've already chosen the best response.0
second derviative goes like this D[ Type function here ,{x,2}]
 11 months ago

modphysnoobBest ResponseYou've already chosen the best response.0
D[(1./(Sqrt[4 Pi t])) * Exp[ x^2/(4 t)], {x, 2}]
 11 months ago

modphysnoobBest ResponseYou've already chosen the best response.0
./ is not used in mathematica, it is matlab notation
 11 months ago

liliyBest ResponseYou've already chosen the best response.0
./ i was just trying to make the whole thing into a number so i tried to multiple (dividde) by 1. lol
 11 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.