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Shadowys
 one year ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow 1}\frac{x^\frac{1}{3}1}{x^\frac{1}{4}1}\] use L'hospital' rule to simplify the statement, as the limit results to 0/0

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0just an alternate way, you could divide numerator and denominator by x1 and use the standard limit, \(\Large \lim \limits_{x\rightarrow a} \dfrac{x^na^n}{xa}=na^{n1}\)

isaacme
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ x^ma }{ x^na}=\frac{ m }{ n }.a ^{mn}\]

sirm3d
 one year ago
Best ResponseYou've already chosen the best response.0you can also try \[x=y^{12}\\x^{1/3}=y^4,\quad x^{1/4}=y^3\] also, when \[x\rightarrow 1,\quad y\rightarrow 1\]
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