Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

zpupster

  • 2 years ago

lim x-->1 x^1/3 -1 over x^1/4 - 1

  • This Question is Closed
  1. Shadowys
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\lim_{x \rightarrow 1}\frac{x^\frac{1}{3}-1}{x^\frac{1}{4}-1}\] use L'hospital' rule to simplify the statement, as the limit results to 0/0

  2. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    just an alternate way, you could divide numerator and denominator by x-1 and use the standard limit, \(\Large \lim \limits_{x\rightarrow a} \dfrac{x^n-a^n}{x-a}=na^{n-1}\)

  3. isaacme
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\frac{ x^m-a }{ x^n-a}=\frac{ m }{ n }.a ^{m-n}\]

  4. sirm3d
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you can also try \[x=y^{12}\\x^{1/3}=y^4,\quad x^{1/4}=y^3\] also, when \[x\rightarrow 1,\quad y\rightarrow 1\]

  5. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy