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Shadowys Group TitleBest ResponseYou've already chosen the best response.1
\[\lim_{x \rightarrow 1}\frac{x^\frac{1}{3}1}{x^\frac{1}{4}1}\] use L'hospital' rule to simplify the statement, as the limit results to 0/0
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
just an alternate way, you could divide numerator and denominator by x1 and use the standard limit, \(\Large \lim \limits_{x\rightarrow a} \dfrac{x^na^n}{xa}=na^{n1}\)
 one year ago

isaacme Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{ x^ma }{ x^na}=\frac{ m }{ n }.a ^{mn}\]
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.0
you can also try \[x=y^{12}\\x^{1/3}=y^4,\quad x^{1/4}=y^3\] also, when \[x\rightarrow 1,\quad y\rightarrow 1\]
 one year ago
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