Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Find the mean and standard deviation of each data set. Round to the nearest hundredth

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

here is 1
1 Attachment
if you hve a scientific calc you can input this in a list and 1 vars stats it to find the mean median and mode
I dont... can u do #1 for me?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

so i came up with a mean of 6
do it FOR you? thats not really why we are here ....
std deviation is 3.8062 good luck :)
the process is tediuos at best ... find the mean by adding up all the values, and dividing that by how many numbers there are this in turn can be used to find the standard deviation ... which in itself is a nightmare to do by hand subtract the mean from each value, and square the results, add up the squares, and divide by how may numbers there are (if its a population); OR divide by one less than that (if its a sample) then take the square root of that result for you standard deviation ...

Not the answer you are looking for?

Search for more explanations.

Ask your own question