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heather040200

  • one year ago

Help! I give medals:) pic below Find the volume.A hemispherical tank has a total surface area of 243pi squared(this includes the circular base area).Show work

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  1. heather040200
    • one year ago
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    |dw:1368065262840:dw|

  2. heather040200
    • one year ago
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    @e.mccormick @timo86m @knock @mathslover think one of u could help me out plezz :)

  3. timo86m
    • one year ago
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    what is the formula for area of a sphere?

  4. heather040200
    • one year ago
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    v=4/3pir^3

  5. timo86m
    • one year ago
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    it's A=4*Pi*r^2 but you want half so 2pi r^2=A solve for r :)

  6. timo86m
    • one year ago
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    2pi r^2=A A/(2 pi)=r^2 divide both sides by 2pi sqrt(A/(2 pi))=r take sqrt of both sides plug in the area in A :) sqrt((243*pi^2)/(2 * pi))=r

  7. knock
    • one year ago
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    I think you should include the surface of the circular base, doesn't?

  8. timo86m
    • one year ago
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    i get like 19.5

  9. heather040200
    • one year ago
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    me to n the surface area they gave me is 243pi squared

  10. heather040200
    • one year ago
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    then do i do SA=1/24pir^2

  11. heather040200
    • one year ago
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    and v=1/2pi cubed

  12. e.mccormick
    • one year ago
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    Did you remember the base in the surface area formula?

  13. heather040200
    • one year ago
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    is it S=B+1/2Cl=pir squared+pirl

  14. razor99
    • one year ago
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    @ heather the volume of a hemisphere is 2/3 pi r^2

  15. heather040200
    • one year ago
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    volume=253.5??

  16. razor99
    • one year ago
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    I mean the formulae

  17. heather040200
    • one year ago
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    so is the volume 253.5??

  18. razor99
    • one year ago
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    me?

  19. heather040200
    • one year ago
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    ya ig

  20. razor99
    • one year ago
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    I guess so

  21. e.mccormick
    • one year ago
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    I got a very different number.

  22. e.mccormick
    • one year ago
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    Find the volume. A hemispherical tank has a total surface area of 243pi squared (this includes the circular base area). Show work Therefore: Half SA of Sphere + A of base = 243 SA Sphere = \(4\pi r^2\) A of Circle = \(\pi r^2\) \[\frac{1}{2}4\pi r^2+\pi r^2=243\\ \implies 3\pi r^2=243\\ \implies \pi r^2=81\\ \implies r^2=\frac{81}{\pi}\\ \implies r=\frac{9}{\sqrt{\pi}}\] Did you follow that for finding the radius?

  23. razor99
    • one year ago
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    To radius I get 4.39 so when it get round off to 2 decimal its 4.40

  24. razor99
    • one year ago
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    This is the volume 356.19

  25. e.mccormick
    • one year ago
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    Or just leave it with the root of pi since that will partially cancel in the next step when doing area. Always save constant conversion until the last step for greater accuracy.

  26. e.mccormick
    • one year ago
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    @razor99 r=4.39? How?

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