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heather040200

Help! I give medals:) pic below Find the volume.A hemispherical tank has a total surface area of 243pi squared(this includes the circular base area).Show work

  • 11 months ago
  • 11 months ago

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  1. heather040200
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    |dw:1368065262840:dw|

    • 11 months ago
  2. heather040200
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    @e.mccormick @timo86m @knock @mathslover think one of u could help me out plezz :)

    • 11 months ago
  3. timo86m
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    what is the formula for area of a sphere?

    • 11 months ago
  4. heather040200
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    v=4/3pir^3

    • 11 months ago
  5. timo86m
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    it's A=4*Pi*r^2 but you want half so 2pi r^2=A solve for r :)

    • 11 months ago
  6. timo86m
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    2pi r^2=A A/(2 pi)=r^2 divide both sides by 2pi sqrt(A/(2 pi))=r take sqrt of both sides plug in the area in A :) sqrt((243*pi^2)/(2 * pi))=r

    • 11 months ago
  7. knock
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    I think you should include the surface of the circular base, doesn't?

    • 11 months ago
  8. timo86m
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    i get like 19.5

    • 11 months ago
  9. heather040200
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    me to n the surface area they gave me is 243pi squared

    • 11 months ago
  10. heather040200
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    then do i do SA=1/24pir^2

    • 11 months ago
  11. heather040200
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    and v=1/2pi cubed

    • 11 months ago
  12. e.mccormick
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    Did you remember the base in the surface area formula?

    • 11 months ago
  13. heather040200
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    is it S=B+1/2Cl=pir squared+pirl

    • 11 months ago
  14. razor99
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    @ heather the volume of a hemisphere is 2/3 pi r^2

    • 11 months ago
  15. heather040200
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    volume=253.5??

    • 11 months ago
  16. razor99
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    I mean the formulae

    • 11 months ago
  17. heather040200
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    so is the volume 253.5??

    • 11 months ago
  18. razor99
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    me?

    • 11 months ago
  19. heather040200
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    ya ig

    • 11 months ago
  20. razor99
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    I guess so

    • 11 months ago
  21. e.mccormick
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    I got a very different number.

    • 11 months ago
  22. e.mccormick
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    Find the volume. A hemispherical tank has a total surface area of 243pi squared (this includes the circular base area). Show work Therefore: Half SA of Sphere + A of base = 243 SA Sphere = \(4\pi r^2\) A of Circle = \(\pi r^2\) \[\frac{1}{2}4\pi r^2+\pi r^2=243\\ \implies 3\pi r^2=243\\ \implies \pi r^2=81\\ \implies r^2=\frac{81}{\pi}\\ \implies r=\frac{9}{\sqrt{\pi}}\] Did you follow that for finding the radius?

    • 11 months ago
  23. razor99
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    To radius I get 4.39 so when it get round off to 2 decimal its 4.40

    • 11 months ago
  24. razor99
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    This is the volume 356.19

    • 11 months ago
  25. e.mccormick
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    Or just leave it with the root of pi since that will partially cancel in the next step when doing area. Always save constant conversion until the last step for greater accuracy.

    • 11 months ago
  26. e.mccormick
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    @razor99 r=4.39? How?

    • 11 months ago
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