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A person scores f(x) = 90/1 + 4e^-0.4t points on a test after t hours of studying. What does the person score without studying at all? Compute f’(0) and estimate how many points 1 hours of studying will add to the score.

Mathematics
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This is what I did but my teacher said it was wrong she said ( Find f' and f'(0).) F(x) = 90/ 1 + 4e^-0.4t F(0) = 90/ 1 + 4e^-0.4(0) = 18 F(1) = 90/1 + 4e^-0.4(1) = 24.45 So comparing the scote at f(1) and f(0) where at f(1) studying for 1 hour and f(0) studying none. F(1) - f(0)/24.45 – 18 = 6.45 points
Should this have parenteses or not? Is this F(x) = 90/ (1 + 4e^-0.4t )?
yes prenthesis

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Other answers:

like this \[\frac{ 9 }{ 1 + 4e ^{-0.4t}}\]
Your teacher specifically said to differentiate?
yes
she said to Find f' and f'(0)
@EulersEquation so do you know how?
@Numb3r1 can u help?
Yes. I need to review this. First glance is to use the quotient rule. Do you know how to use the quotient rule? Someone else may want to take a look. I am in the middle of helping someone else. When I finish I'll get on it.
ok
Ha! I am terrible at arithmetic. On first run I get a negative number for f'(0). You cannot make a negative score on a test! Unless the teacher doesn't like you. I am rusty on this. I'll work on it some more. In the meantime, bump the problem and hopefully someone else will tackle this.
okay
Just want to take derivative of that??
yes Find f' and f'(0)
It will come out to be negative..
what will come out? so what i did above is wrong or?
Wait, let we do it first..
\[\frac{ 90 }{ 1 + 4e ^{-0.4t}} = \frac{ -(90)(-1.6 \cdot e^{-0.4t}) }{ (1 + 4e ^{-0.4t})^2}\]
It will become positive now.. :)
okay
Yeah. I don't see why it has to be differentiated -- not according to the question.
Am I right in this?
Ah! I forgot to square the denominator!
That looks good.
okay thanks!
So you can now find f'(0) by putting 0 as value of t..
okay
@onegirl can you go for that?
just plug in 0 and solve right?
Yep, just simple calculations with calculator..
okay yes i can
Good.. Keep it up..
i got 0 after i solved

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