## veritos 2 years ago A square has a perimeter of 12 units. One of its vertices is at (5, –2). Which of the following are possible coordinates of another vertex? Recall that perimeter is the sum of the lengths of the sides.

1. mathstudent55

Since the perimeter is 12 units, what is the length of each side?

2. veritos

(8,-2)

3. veritos

?

4. mathstudent55

That could be a vertex.

5. veritos

its correct?

6. mathstudent55

(8, -2) is a possible vertex since it's 3 units away from the given point.

7. veritos

sorry but i cant understand

Becuase you use the computer so much as you are a student you can download the free graphing program GeoGebra to learn how to find the vertex's. Now as for the length you can check and see if you are right with the length formula.

9. veritos

Do you know what the term perimeter stands for?

11. mathstudent55

I asked you a question in the beginning. If you answer my questions, I'll explain it to you. Let's start again. If the perimeter of the square is 12 units, how long is each side?

12. veritos

3

Area is when you multiply the length times the width. perimeter is when you add all of the sides. That being said you would divide the perimeter by 4 (4 standing for each side of the square.) Then you would have the length of each side which is three. Now, in order to find each possible vertex on a graph you would draw it out! So you would go three units each way until you have the finished square. Then you take all of those points and you can say each of those is a possible vertex.

15. veritos

(9,-2) (8,-2) (5,5) (5,-1)

This is not one of those questions we can answer for you. You actually have to draw it out and find which point would work. That or take each set and put them into the formula:$d= \sqrt{(x _{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}}$

When you put them into the formula to find the distance between the original vertex that you know and the second one it has to equal 3 in order for that to be a possible answer.

18. veritos

(8,-2) maybe?

Welcome to OpenStudy by the way!

20. veritos

The are taking about is finding the distance on the coordinate plane

Exactly that is where the equation above comes in!

Here is what you can do...Take all of the choices work them into that equation along with the original vertex they have given you and if the disance is 3 it is a possible choice

23. veritos

ok thank you