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veritos

A square has a perimeter of 12 units. One of its vertices is at (5, –2). Which of the following are possible coordinates of another vertex? Recall that perimeter is the sum of the lengths of the sides.

  • 11 months ago
  • 11 months ago

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  1. mathstudent55
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    Since the perimeter is 12 units, what is the length of each side?

    • 11 months ago
  2. veritos
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    (8,-2)

    • 11 months ago
  3. veritos
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    ?

    • 11 months ago
  4. mathstudent55
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    That could be a vertex.

    • 11 months ago
  5. veritos
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    its correct?

    • 11 months ago
  6. mathstudent55
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    (8, -2) is a possible vertex since it's 3 units away from the given point.

    • 11 months ago
  7. veritos
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    sorry but i cant understand

    • 11 months ago
  8. SnuggieLad
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    Becuase you use the computer so much as you are a student you can download the free graphing program GeoGebra to learn how to find the vertex's. Now as for the length you can check and see if you are right with the length formula.

    • 11 months ago
  9. veritos
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    thank you for your help

    • 11 months ago
  10. SnuggieLad
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    Do you know what the term perimeter stands for?

    • 11 months ago
  11. mathstudent55
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    I asked you a question in the beginning. If you answer my questions, I'll explain it to you. Let's start again. If the perimeter of the square is 12 units, how long is each side?

    • 11 months ago
  12. veritos
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    3

    • 11 months ago
  13. SnuggieLad
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    Area is when you multiply the length times the width. perimeter is when you add all of the sides. That being said you would divide the perimeter by 4 (4 standing for each side of the square.) Then you would have the length of each side which is three. Now, in order to find each possible vertex on a graph you would draw it out! So you would go three units each way until you have the finished square. Then you take all of those points and you can say each of those is a possible vertex.

    • 11 months ago
  14. SnuggieLad
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    So what are your multiple choice answers.

    • 11 months ago
  15. veritos
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    (9,-2) (8,-2) (5,5) (5,-1)

    • 11 months ago
  16. SnuggieLad
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    This is not one of those questions we can answer for you. You actually have to draw it out and find which point would work. That or take each set and put them into the formula:\[d= \sqrt{(x _{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}}\]

    • 11 months ago
  17. SnuggieLad
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    When you put them into the formula to find the distance between the original vertex that you know and the second one it has to equal 3 in order for that to be a possible answer.

    • 11 months ago
  18. veritos
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    (8,-2) maybe?

    • 11 months ago
  19. SnuggieLad
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    Welcome to OpenStudy by the way!

    • 11 months ago
  20. veritos
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    The are taking about is finding the distance on the coordinate plane

    • 11 months ago
  21. SnuggieLad
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    Exactly that is where the equation above comes in!

    • 11 months ago
  22. SnuggieLad
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    Here is what you can do...Take all of the choices work them into that equation along with the original vertex they have given you and if the disance is 3 it is a possible choice

    • 11 months ago
  23. veritos
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    ok thank you

    • 11 months ago
  24. SnuggieLad
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    Don't forget to fan and best the answers!

    • 11 months ago
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