anonymous
  • anonymous
A square has a perimeter of 12 units. One of its vertices is at (5, –2). Which of the following are possible coordinates of another vertex? Recall that perimeter is the sum of the lengths of the sides.
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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mathstudent55
  • mathstudent55
Since the perimeter is 12 units, what is the length of each side?
anonymous
  • anonymous
(8,-2)
anonymous
  • anonymous
?

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mathstudent55
  • mathstudent55
That could be a vertex.
anonymous
  • anonymous
its correct?
mathstudent55
  • mathstudent55
(8, -2) is a possible vertex since it's 3 units away from the given point.
anonymous
  • anonymous
sorry but i cant understand
SnuggieLad
  • SnuggieLad
Becuase you use the computer so much as you are a student you can download the free graphing program GeoGebra to learn how to find the vertex's. Now as for the length you can check and see if you are right with the length formula.
anonymous
  • anonymous
thank you for your help
SnuggieLad
  • SnuggieLad
Do you know what the term perimeter stands for?
mathstudent55
  • mathstudent55
I asked you a question in the beginning. If you answer my questions, I'll explain it to you. Let's start again. If the perimeter of the square is 12 units, how long is each side?
anonymous
  • anonymous
3
SnuggieLad
  • SnuggieLad
Area is when you multiply the length times the width. perimeter is when you add all of the sides. That being said you would divide the perimeter by 4 (4 standing for each side of the square.) Then you would have the length of each side which is three. Now, in order to find each possible vertex on a graph you would draw it out! So you would go three units each way until you have the finished square. Then you take all of those points and you can say each of those is a possible vertex.
SnuggieLad
  • SnuggieLad
So what are your multiple choice answers.
anonymous
  • anonymous
(9,-2) (8,-2) (5,5) (5,-1)
SnuggieLad
  • SnuggieLad
This is not one of those questions we can answer for you. You actually have to draw it out and find which point would work. That or take each set and put them into the formula:\[d= \sqrt{(x _{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}}\]
SnuggieLad
  • SnuggieLad
When you put them into the formula to find the distance between the original vertex that you know and the second one it has to equal 3 in order for that to be a possible answer.
anonymous
  • anonymous
(8,-2) maybe?
SnuggieLad
  • SnuggieLad
Welcome to OpenStudy by the way!
anonymous
  • anonymous
The are taking about is finding the distance on the coordinate plane
SnuggieLad
  • SnuggieLad
Exactly that is where the equation above comes in!
SnuggieLad
  • SnuggieLad
Here is what you can do...Take all of the choices work them into that equation along with the original vertex they have given you and if the disance is 3 it is a possible choice
anonymous
  • anonymous
ok thank you
SnuggieLad
  • SnuggieLad
Don't forget to fan and best the answers!

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