anonymous
  • anonymous
Felipe can choose 1 snack from a box containing 3 different granola bars, 4 different kinds of fruit, and 2 different kinds of chips. How many ways can Felipe choose a snack?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
thank you
anonymous
  • anonymous
Isn't it 3 * 4 * 2 ?
anonymous
  • anonymous
\[\frac{ possible_choices! }{ 3_different_granola_bars! * 4_different_kinds_of_fruit! * 2_different_kinds_of_chips! }\]

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anonymous
  • anonymous
\[\frac{ 9! }{ 3!4!2! }\]
anonymous
  • anonymous
yea
anonymous
  • anonymous
A. 5 B. 9 C. 14 D. 24
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
Erm, I think it's 24.
anonymous
  • anonymous
anonymous
  • anonymous
lol
anonymous
  • anonymous
Well. Yeah, I'm pretty sure it is 24. :-P
anonymous
  • anonymous
ok, wat abut you @EulersEquation
anonymous
  • anonymous
just 2 be sure
anonymous
  • anonymous
r u even there @EulersEquation ?
anonymous
  • anonymous
NO, I guess it is 3 * 4 * 2. Did someone say that already?
anonymous
  • anonymous
I was doing a stupid permutation.
anonymous
  • anonymous
@EulersEquation Haha, yeah. ^_^
anonymous
  • anonymous
I was wondering wat that was. lol ">"
anonymous
  • anonymous
@EulersEquation ? is it 24?
anonymous
  • anonymous
is it 24? @Luis_Rivera
anonymous
  • anonymous
thx
anonymous
  • anonymous
ACTUALLY the answer is 9. The problem says that he can choose one snack from 9 choices! You see? The question is worded poorly. Does it mean one snack containing one of each of the three types of snacks? Or does it mean only one thing among the nine items?
anonymous
  • anonymous
dude, i know what it meant

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