anonymous
  • anonymous
Half-Life Un-decayed atoms Decayed Atoms What is this Toss# What is this Parents What is this Daughter 0 100 0 1 45 55 2 25 20 3 13 12 4 6 7 5 3 3 6 1 2 7 0 1 8 0 0 Data Analysis: Answer this Analyze your data question: How many un-decayed atoms of an element will remain after 2.5 half-lives?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
@joannaxox3 @joyce153 @kevincourtes @heyheyhelpme help me please
anonymous
  • anonymous
please help i will give you a medal
anonymous
  • anonymous
idk bye?

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anonymous
  • anonymous
How many un-decayed atoms of an element will remain after 2.5 half-lives? this is the question
anonymous
  • anonymous
@jen1511 @kymy_rose00 @LoveYou*69 @galacticwavesXX please help
anonymous
  • anonymous
the data is confusing. What does each column represent?
anonymous
  • anonymous
wait
anonymous
  • anonymous
tess# un-decay atoms decay atoms 0 100 0 1 45 55 2 25 20 3 13 12 4 6 7 5 3 3 6 1 2 7 0 1 8 0 0
anonymous
  • anonymous
please help me! i really need help
anonymous
  • anonymous
@heathernelly @Kayy_Drizzyy @lala2 @o.Ohuh? @Ashleyisakitty
anonymous
  • anonymous
i honestly dont know....i would need sometime to remember how to do half-lives from given data tables
anonymous
  • anonymous
oh please someone else
anonymous
  • anonymous
i willgive medal
anonymous
  • anonymous
pleasseeeee
anonymous
  • anonymous
what i am thinking you have to do is use the formula \[N(t)=N _{0}e^(kt)\] the problem is that we don't have anything in the data hat indicates time
anonymous
  • anonymous
thats is e^kt idk why it came out like that
anonymous
  • anonymous
are you sure you didnt leave out any givens that would help us?
anonymous
  • anonymous
let me see
anonymous
  • anonymous
Half-Life Un-decayed atoms Decayed Atoms What is this Toss# What is this Parents What is this Daughter 0 100 0 1 45 55 2 25 20 3 13 12 4 6 7 5 3 3 6 1 2 7 0 1 8 0 0 Data Analysis: Answer this Analyze your data question: How many un-decayed atoms of an element will remain after 2.5 half-lives? no that was all

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