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This is what i did but my teacher says it wrong. C(x) = 0.02x^2 + 20x + 1800 C’(x) = 0.04x + 20 C’(20) = 0.04(20) + 20 = 20.8 so this will be the marginal cost at x = 20 Acutal cost of the 20th item : c(20) - c(19) = 0.02(20^2) + 20(20) + 1800 – 0.02(19)^2 + 20(19) + 1800 = 4380.78
@agent0smith can u help?
c(20)-c(19) = 2208 - 2187,22 = 20.78 it is just one algebraic mistake
okay thanks so thats the marginal cost?
no! u already got the amrginal cost "C’(20) = 0.04(20) + 20 = 20.8 so this will be the marginal cost at x = 20 "
ohh okay so what do i do next?
u wrote this "Acutal cost of the 20th item : c(20) - c(19) = 0.02(20^2) + 20(20) + 1800 – 0.02(19)^2 + 20(19) + 1800 = 4380.78 " i m telling u that part is wrong with algebraic mistakes
so you're saying in that its where i made my sitake?
i made that calculations and i got c(20)-c(19) = 2208 - 2187,22 = 20.78
so how about the actual cost?
@Loser66 so how would i find the actual cost? should i just substitute 20 into the first problem?
sorry friend, I totally lost you in this question. I don't get why you subtract C(20 ) -C(19)
to get the marginal cost? i'm so confused :/
I know why don't get you, hihi, it's economic problem. hand off, friend. never known before
hi again so what part u dont understand i think the problem is done
i'm trying to figure it out what is the actual cost is? since we already found marginal cost
u have the marginal cost C’(x) = 0.04x + 20 C’(20) = 0.04(20) + 20 = 20.8 and the actual cost of producing the 20th item. c(20)-c(19) = 2208 - 2187,22 = 20.78 the problem says that u must compare them and u can can see they r very close
how how do i do that?
how to do what? compare them? 20.8 is very close to 20.78 u dont need to do anymore