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indianwaking97

  • one year ago

What is the solution of X^2+64=0? -5 8 +-8 no solution

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  1. mikelo40
    • one year ago
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    Simplifying x2 + -64 = 0 Reorder the terms: -64 + x2 = 0 Solving -64 + x2 = 0 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '64' to each side of the equation. -64 + 64 + x2 = 0 + 64 Combine like terms: -64 + 64 = 0 0 + x2 = 0 + 64 x2 = 0 + 64 Combine like terms: 0 + 64 = 64 x2 = 64 Simplifying x2 = 64 Take the square root of each side: x = {-8, 8}

  2. brookester6
    • one year ago
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    x=8

  3. brookester6
    • one year ago
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    x=-8 too it's both

  4. mikelo40
    • one year ago
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    ^ :D

  5. brookester6
    • one year ago
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    lol

  6. indianwaking97
    • one year ago
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    Thanks:)

  7. mikelo40
    • one year ago
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    Np.

  8. brookester6
    • one year ago
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    np :D

  9. brookester6
    • one year ago
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    haha

  10. Spacelimbus
    • one year ago
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    \[x^2+64=0 \] has only solutions in \[ \mathbb{C}\] though

  11. brookester6
    • one year ago
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    no because you subtract 64 then it's x^2 = 64 and then you square root it all :) which is x=8 or x=-8 :D

  12. brookester6
    • one year ago
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    ur finding x not b or c

  13. Spacelimbus
    • one year ago
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    yes, can you take the square root from a negative number?

  14. Spacelimbus
    • one year ago
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    Take a look at this: http://www.wolframalpha.com/input/?i=x%5E2%2B64%3D0

  15. brookester6
    • one year ago
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    i just know the answer i'm not really good at other things :/ sorry

  16. Spacelimbus
    • one year ago
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    Anyway, in Reals this one has no answer, so -> no solution

  17. brookester6
    • one year ago
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    ummm idk O.o i think it's x= -8;8

  18. Spacelimbus
    • one year ago
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    Just check then, if x=8 is your solution, plug it into your equation and tell me if that gives you zero. \[x^2+64=0\] so you say x=8 \[(8)^2+64=64+64=128 \neq 0 \]

  19. Spacelimbus
    • one year ago
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    Now check for your other solution, you say x=-8 is a solution, so you plug that one in too: \[(-8)^2+64=64+64=128\neq0\]

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