anonymous
  • anonymous
What is the solution of X^2+64=0? -5 8 +-8 no solution
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Simplifying x2 + -64 = 0 Reorder the terms: -64 + x2 = 0 Solving -64 + x2 = 0 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '64' to each side of the equation. -64 + 64 + x2 = 0 + 64 Combine like terms: -64 + 64 = 0 0 + x2 = 0 + 64 x2 = 0 + 64 Combine like terms: 0 + 64 = 64 x2 = 64 Simplifying x2 = 64 Take the square root of each side: x = {-8, 8}
anonymous
  • anonymous
x=8
anonymous
  • anonymous
x=-8 too it's both

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anonymous
  • anonymous
^ :D
anonymous
  • anonymous
lol
anonymous
  • anonymous
Thanks:)
anonymous
  • anonymous
Np.
anonymous
  • anonymous
np :D
anonymous
  • anonymous
haha
anonymous
  • anonymous
\[x^2+64=0 \] has only solutions in \[ \mathbb{C}\] though
anonymous
  • anonymous
no because you subtract 64 then it's x^2 = 64 and then you square root it all :) which is x=8 or x=-8 :D
anonymous
  • anonymous
ur finding x not b or c
anonymous
  • anonymous
yes, can you take the square root from a negative number?
anonymous
  • anonymous
Take a look at this: http://www.wolframalpha.com/input/?i=x%5E2%2B64%3D0
anonymous
  • anonymous
i just know the answer i'm not really good at other things :/ sorry
anonymous
  • anonymous
Anyway, in Reals this one has no answer, so -> no solution
anonymous
  • anonymous
ummm idk O.o i think it's x= -8;8
anonymous
  • anonymous
Just check then, if x=8 is your solution, plug it into your equation and tell me if that gives you zero. \[x^2+64=0\] so you say x=8 \[(8)^2+64=64+64=128 \neq 0 \]
anonymous
  • anonymous
Now check for your other solution, you say x=-8 is a solution, so you plug that one in too: \[(-8)^2+64=64+64=128\neq0\]

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