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mikelo40
 one year ago
Best ResponseYou've already chosen the best response.0Simplifying x2 + 64 = 0 Reorder the terms: 64 + x2 = 0 Solving 64 + x2 = 0 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '64' to each side of the equation. 64 + 64 + x2 = 0 + 64 Combine like terms: 64 + 64 = 0 0 + x2 = 0 + 64 x2 = 0 + 64 Combine like terms: 0 + 64 = 64 x2 = 64 Simplifying x2 = 64 Take the square root of each side: x = {8, 8}

brookester6
 one year ago
Best ResponseYou've already chosen the best response.1x=8 too it's both

Spacelimbus
 one year ago
Best ResponseYou've already chosen the best response.1\[x^2+64=0 \] has only solutions in \[ \mathbb{C}\] though

brookester6
 one year ago
Best ResponseYou've already chosen the best response.1no because you subtract 64 then it's x^2 = 64 and then you square root it all :) which is x=8 or x=8 :D

brookester6
 one year ago
Best ResponseYou've already chosen the best response.1ur finding x not b or c

Spacelimbus
 one year ago
Best ResponseYou've already chosen the best response.1yes, can you take the square root from a negative number?

Spacelimbus
 one year ago
Best ResponseYou've already chosen the best response.1Take a look at this: http://www.wolframalpha.com/input/?i=x%5E2%2B64%3D0

brookester6
 one year ago
Best ResponseYou've already chosen the best response.1i just know the answer i'm not really good at other things :/ sorry

Spacelimbus
 one year ago
Best ResponseYou've already chosen the best response.1Anyway, in Reals this one has no answer, so > no solution

brookester6
 one year ago
Best ResponseYou've already chosen the best response.1ummm idk O.o i think it's x= 8;8

Spacelimbus
 one year ago
Best ResponseYou've already chosen the best response.1Just check then, if x=8 is your solution, plug it into your equation and tell me if that gives you zero. \[x^2+64=0\] so you say x=8 \[(8)^2+64=64+64=128 \neq 0 \]

Spacelimbus
 one year ago
Best ResponseYou've already chosen the best response.1Now check for your other solution, you say x=8 is a solution, so you plug that one in too: \[(8)^2+64=64+64=128\neq0\]
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