ValentinaT
Identify the asymptotes of the graph of each function. Then graph the function.



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ValentinaT
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\[y = \frac{ 1 }{ x + 2 }\]

Mertsj
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The vertical asymptote occurs where the denominator is 0. What value of x makes the denominator 0?

ValentinaT
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2.

Mertsj
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So the vertical asymptote is x = 2

ValentinaT
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Okay, now to graph the function.

Mertsj
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dw:1368222257318:dw

Mertsj
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Now we know that the degree of the numerator is less than the degree of the denominator so that means that the y axis is a horizontal asymptote.

Mertsj
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So you need to figure out which two areas the two branches will be in.

Mertsj
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dw:1368222410758:dw

Mertsj
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Can you figure that out?