Evaluate the definite integral.

- anonymous

Evaluate the definite integral.

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- schrodinger

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- anonymous

##### 1 Attachment

- anonymous

go into this site callec web 2.0 calc it type the problem into the calculator and BAM theres the answer! :) or better yet, get out paper and actually write out the problem

- anonymous

and solve it that way

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## More answers

- Loser66

@onegirl do you have any idea?

- anonymous

am i just going to substitute u or?

- Loser66

yes, which one? u =?

- Loser66

try u = x^2 +1 then du =?

- anonymous

is du the derivative of it? or

- Loser66

yes!! try, if you make some mistake, i correct it then, but the most important is trying!!

- anonymous

ok

- Loser66

don't worry, I dare not say anything further, but to this problem, I am ok

- anonymous

okay i'll try it t

- anonymous

okay for the derivative i got 2x

- Loser66

2xdx girl. ok, let put it in neat du = 2x dx , right?

- Loser66

got it?

- anonymous

okay

- Loser66

ok, now, we change the limit, have to. tell me, if x =0, u =?

- Loser66

do you know what I am doing?

- anonymous

hmmm no

- Loser66

ok, let me explain. Originally, you have x, dx and limits respect to x
then, you change (substitute) to u, so, dx must change to du and limits must follow u, right?

- anonymous

yes

- anonymous

so u will be 0 too right?

- anonymous

Me? I live in USA

- Loser66

ok, take step!! forget my question, I thought you don't understand what I mean so, made that question to find out another way for you to come up the problem, now, you got it, no need more . take a look

- anonymous

ok lol my bad

- Loser66

|dw:1368223122327:dw|

- Loser66

calculate it and tell me the answer

- Loser66

|dw:1368223207231:dw|

- anonymous

umm 5?

- Loser66

perfect! now replace

- Loser66

|dw:1368223296128:dw|

- anonymous

ok

- Loser66

you go girl!!! can step up from here?

- anonymous

so now i find the integral or?

- Loser66

am I rude when saying that? sorry if you feel so, or I take it back?

- anonymous

noo is that a sqrt sign?

- Loser66

yep, from the beginning until now, we don't "substitute " that sqrt, so it's there still

- anonymous

okay

- Loser66

so, what's the answer?

- anonymous

so i got (2 u^(3/2))/3+C

- Loser66

something wrong there,
1st you forgot 1/2 from du, and it cancel out with your 2/3 to get 1/3 only
2nd, it has a limits so, you have to replace those limit where you have u.

- Loser66

|dw:1368223960531:dw|

- Loser66

|dw:1368224029766:dw|
that's the final one

- anonymous

ohhh okay

- Loser66

glad to hear that.

- anonymous

thanks!

- Loser66

yw

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