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Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2It might be easier to write it like this: \[s=t^4+3t ^{1}+3t ^{2}\]

sasogeek
 one year ago
Best ResponseYou've already chosen the best response.0@iplayffxiv can you continue from the help @Mertsj has provided?

iplayffxiv
 one year ago
Best ResponseYou've already chosen the best response.0i dont understand that

sasogeek
 one year ago
Best ResponseYou've already chosen the best response.0He simplified the equation first. now it will be easier to find the derivatives :) still lost? here's a simple way to find a derivative: if \(\large y=ax^n \) the derivative \(\large dy \), is equal to \(\large dy=nax^{n1} \)

sasogeek
 one year ago
Best ResponseYou've already chosen the best response.0\(\large a \) is a constant, if \(\large a \) is 1, it is not written

iplayffxiv
 one year ago
Best ResponseYou've already chosen the best response.0does not make sense to me. it is multiple choice. can you choose the right answer?

sasogeek
 one year ago
Best ResponseYou've already chosen the best response.0first derivative: \(\large s=4t^33t^{2}6t^{3} \) apply the same trick to see if you get ur answer.... take ur time, shouldn't be that difficult :)

iplayffxiv
 one year ago
Best ResponseYou've already chosen the best response.0A) d2s/dt2 = 4t^3 3/t2 6/t3 B) d2s/dt2 = 12t^4 +6/t +18/t2 C) d2s/dt2 = 4t^2 3/t3 6/t4 D) d2s/dt2 = 12t^2 +6/t^3 +18/t4

sasogeek
 one year ago
Best ResponseYou've already chosen the best response.0find the derivative of \(\large 4t^3 \), your answer will be obvious :) remember, the derivative of \(\large ax^n =nax^{n1} \)

iplayffxiv
 one year ago
Best ResponseYou've already chosen the best response.0i dont know what to do

sasogeek
 one year ago
Best ResponseYou've already chosen the best response.0do well to read on how to find derivatives, but the answer you're looking for is the last option

iplayffxiv
 one year ago
Best ResponseYou've already chosen the best response.0someone give me answer

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2Do you want to learn to do this or do you just want an answer?

iplayffxiv
 one year ago
Best ResponseYou've already chosen the best response.0i would like to have the answer

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2Then we are all leaving because OS is not an answering service. Goodbye and good luck. All the time that has been spent on this problem was ample for you to learn to do i had you so chosen.
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