A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
'A' and 'B' can do a piece of work in 25 days and 30 days respectively. Both start the work together but 'A' leaves the work 8 days before its completion. Find the time in which the work is finished.
 one year ago
'A' and 'B' can do a piece of work in 25 days and 30 days respectively. Both start the work together but 'A' leaves the work 8 days before its completion. Find the time in which the work is finished.

This Question is Open

stgreen
 one year ago
Best ResponseYou've already chosen the best response.3'A' can do 1/25 job per day 'B' can do 1/30 job per day part of job done in 8 days=8(1/25 + 1/30) part of job done in rest of days (by 'B' alone)=1[8(1/25 + 1/30)] days consumed to finish job by 'B'=(1/25)*[1[8(1/25 + 1/30)]] total days to finish job=8+(1/25)*[1[8(1/25 + 1/30)]]

stgreen
 one year ago
Best ResponseYou've already chosen the best response.3do calculations youself>>make yourself useful

Jas9420
 one year ago
Best ResponseYou've already chosen the best response.1Now, the time taken by A and B to complete 22/30th work is \[\frac{ 22 }{ 30 }\times \frac{ 210 }{ 11}\] And for the total, number of days, you'll have to add an 8 it.

sasogeek
 one year ago
Best ResponseYou've already chosen the best response.0stgreen, A leaves the job 8 days BEFORE COMPLETION.... not 8 days after they began.... so that's how long they would've taken to finish minus 8... correct?

stgreen
 one year ago
Best ResponseYou've already chosen the best response.3oh right i didn't see that

Jas9420
 one year ago
Best ResponseYou've already chosen the best response.1It's 14 + 8 = 22 days, I think.

stgreen
 one year ago
Best ResponseYou've already chosen the best response.3if both work they take 14 days to finish

stgreen
 one year ago
Best ResponseYou've already chosen the best response.3so A left after 6 days

stgreen
 one year ago
Best ResponseYou've already chosen the best response.3'A' can do 1/25 job per day 'B' can do 1/30 job per day part of job done in 6 days=6(1/25 + 1/30) part of job done in rest of days (by 'B' alone)=1[6(1/25 + 1/30)] days consumed to finish job by 'B'=(1/25)*[1[6(1/25 + 1/30)]] total days to finish job=6+(1/25)*[1[6(1/25 + 1/30)]]

Jas9420
 one year ago
Best ResponseYou've already chosen the best response.1Oh, now I get it. No. of days A and B take to do 1 work: 1/25 + 1/ 30 = 11/ 150= 150/11 In one day, B can do : 8/30th of work. So, the remaining work is done by both A and B. The remaining work is : 22/30 Now, the time taken by A and B to complete 22/30th work is :\[ \frac{ 22 }{ 30 } \times \frac{ 150 }{ 11 } = 10 days.\] So, total = 10 + 8 = 18 days.

phi
 one year ago
Best ResponseYou've already chosen the best response.1I would use rate * time = "distance" or in this case \[ \frac{\text{jobs}}{\text{day}}\cdot { \text{days} }= \text{# of jobs} \] let T = total number of days for the job. B works for all T days, A works for T8 days we have \[ \frac{1}{25} \cdot (T8) + \frac{1}{30} T = 1 \] multiply both sides by 30*25 to "clear" the denominators \[ 30 (T8) + 25 T= 750 \\ 55T = 990 \\ T= 18 \]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.