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How can one make a standard solution of 0.002 mol dm^-3 KOH ? Thanks:)

Chemistry
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you want to prepare 1 liter of 0.002 Molar solution of KOH molar mass of KOH is = 56.10 56.10 gram in 1000 ml (1LITRE) =1M 5.610 gram in 1000 ml =0.1M 0.5610 gram in 1000 ml = 0.01M 0.05610 gram in 1000 ml =0.001M 0.05610*2 gram in 1000 ml = 0.002 M 0.112 gramin 1000ml =0.002M
short cut is also there but it is just simple and lengthy procedure :)
oh ok thanks :)

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ur welcome :)

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