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bowlinL7252
Group Title
Hi guys, one question with a couple of parts!
What is the oxidation state for the atoms in the reaction:
2Al + 8H2O → 2H+1 + 3H2 + 2Al(OH)41
a) Elemental aluminum (Al)
b) One hydrogen atom in H2O
c) One oxygen atom in H20
d) Elemental hydrogen (H)
e) One aluminum atom in Al(OH)41
f) One oxygen atom in Al(OH)41
g) One hydrogen atom in Al(OH)41
 one year ago
 one year ago
bowlinL7252 Group Title
Hi guys, one question with a couple of parts! What is the oxidation state for the atoms in the reaction: 2Al + 8H2O → 2H+1 + 3H2 + 2Al(OH)41 a) Elemental aluminum (Al) b) One hydrogen atom in H2O c) One oxygen atom in H20 d) Elemental hydrogen (H) e) One aluminum atom in Al(OH)41 f) One oxygen atom in Al(OH)41 g) One hydrogen atom in Al(OH)41
 one year ago
 one year ago

This Question is Closed

aaronq Group TitleBest ResponseYou've already chosen the best response.1
oxidation state on homonuclear molecules or elemental species = 0
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
Oxygen = 2 always
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
you can figure out the rest by balancing the charges
 one year ago

bowlinL7252 Group TitleBest ResponseYou've already chosen the best response.0
Alright, so for a i got 0, b 3, c 2, d 1, e 2, f 2 and g 0. Are these right?
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.1
Let me see if I get this right: You suggest that hydrogen in water have the oxidation number 3?
 one year ago

bowlinL7252 Group TitleBest ResponseYou've already chosen the best response.0
I believe so
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.1
Okay. We need an additional rule: "The sum of oxidations numbers most equal to total charge of the molecule." So when we look at water it have no charge... sense oxygen always get 2 each hydrogen most be what?
 one year ago

bowlinL7252 Group TitleBest ResponseYou've already chosen the best response.0
5? And in that equation, which element was reduced and which was oxidized?
 one year ago

bowlinL7252 Group TitleBest ResponseYou've already chosen the best response.0
And can verify my answers please?
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.1
Best you get some training, so I'm gonna start with water and we take them each by each. H2O we take notice: Total charge = 0 oxygen always 2 Hydrogen always +1 This also make sense we should say: 0=2+2*x <> x=+1
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.1
aluminum is right. again it does not have charge and is an elemental species.
 one year ago

bowlinL7252 Group TitleBest ResponseYou've already chosen the best response.0
Both hydrogens are positive one as well?
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.1
Yes. it is 2 times +1
 one year ago

bowlinL7252 Group TitleBest ResponseYou've already chosen the best response.0
Alright, so what about for e through g?
 one year ago

bowlinL7252 Group TitleBest ResponseYou've already chosen the best response.0
hello?
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.1
Sorry I was thinking. both e and g are wrong.
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.1
The oxidation state of oxygen is 2 the oxidation state of hydrogen is +1: so we get: Al(OH)4 1 1 = 8+4+x Here is x the oxidation state of Al.. What is x?
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.1
Not quite.
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.1
\[1=8+4+x\] \[x=1+84=3\]
 one year ago

bowlinL7252 Group TitleBest ResponseYou've already chosen the best response.0
So aluminum was reduced, so which was oxidized?
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
which one are you working on?
 one year ago

bowlinL7252 Group TitleBest ResponseYou've already chosen the best response.0
I need the answer for g and then: In the equation above, which element was reduced and which element was oxidized?
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
The H on the compound is part of the hydroxide ion, which is OH^ since O is 2 and theres a 1 charge on ion, H is +1
 one year ago

bowlinL7252 Group TitleBest ResponseYou've already chosen the best response.0
Awesome. so then which was oxidized and which was reduced?
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
they're both 0 when not part of a molecule, if one gains e then we say its reduced because it became more negative, the opposite is for oxidized.
 one year ago

bowlinL7252 Group TitleBest ResponseYou've already chosen the best response.0
I mean for all of the elements in the equations, it seems like aluminum gained electrons
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
we already did everything in the equation
 one year ago
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