anonymous
  • anonymous
Hi guys, one question with a couple of parts! What is the oxidation state for the atoms in the reaction: 2Al + 8H2O → 2H+1 + 3H2 + 2Al(OH)4-1 a) Elemental aluminum (Al) b) One hydrogen atom in H2O c) One oxygen atom in H20 d) Elemental hydrogen (H) e) One aluminum atom in Al(OH)4-1 f) One oxygen atom in Al(OH)4-1 g) One hydrogen atom in Al(OH)4-1
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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aaronq
  • aaronq
oxidation state on homonuclear molecules or elemental species = 0
aaronq
  • aaronq
Oxygen = -2 always
aaronq
  • aaronq
you can figure out the rest by balancing the charges

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More answers

anonymous
  • anonymous
Alright, so for a i got 0, b -3, c -2, d 1, e 2, f -2 and g 0. Are these right?
Frostbite
  • Frostbite
Let me see if I get this right: You suggest that hydrogen in water have the oxidation number -3?
anonymous
  • anonymous
I believe so
Frostbite
  • Frostbite
Okay. We need an additional rule: "The sum of oxidations numbers most equal to total charge of the molecule." So when we look at water it have no charge... sense oxygen always get -2 each hydrogen most be what?
anonymous
  • anonymous
-5? And in that equation, which element was reduced and which was oxidized?
anonymous
  • anonymous
And can verify my answers please?
Frostbite
  • Frostbite
Best you get some training, so I'm gonna start with water and we take them each by each. H2O we take notice: Total charge = 0 oxygen always -2 Hydrogen always +1 This also make sense we should say: 0=-2+2*x <-> x=+1
Frostbite
  • Frostbite
aluminum is right. again it does not have charge and is an elemental species.
anonymous
  • anonymous
Both hydrogens are positive one as well?
Frostbite
  • Frostbite
Yes. it is 2 times +1
anonymous
  • anonymous
Alright, so what about for e through g?
anonymous
  • anonymous
hello?
Frostbite
  • Frostbite
Sorry I was thinking. both e and g are wrong.
Frostbite
  • Frostbite
The oxidation state of oxygen is -2 the oxidation state of hydrogen is +1: so we get: Al(OH)4 -1 -1 = -8+4+x Here is x the oxidation state of Al.. What is x?
Frostbite
  • Frostbite
Not quite.
Frostbite
  • Frostbite
\[-1=-8+4+x\] \[x=-1+8-4=3\]
anonymous
  • anonymous
So aluminum was reduced, so which was oxidized?
aaronq
  • aaronq
which one are you working on?
anonymous
  • anonymous
g
anonymous
  • anonymous
I need the answer for g and then: In the equation above, which element was reduced and which element was oxidized?
aaronq
  • aaronq
The H on the compound is part of the hydroxide ion, which is OH^- since O is -2 and theres a -1 charge on ion, H is +1
anonymous
  • anonymous
Awesome. so then which was oxidized and which was reduced?
aaronq
  • aaronq
they're both 0 when not part of a molecule, if one gains e then we say its reduced because it became more negative, the opposite is for oxidized.
anonymous
  • anonymous
I mean for all of the elements in the equations, it seems like aluminum gained electrons
anonymous
  • anonymous
!
aaronq
  • aaronq
we already did everything in the equation

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