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bowlinL7252

  • 2 years ago

Hi guys, one question with a couple of parts! What is the oxidation state for the atoms in the reaction: 2Al + 8H2O → 2H+1 + 3H2 + 2Al(OH)4-1 a) Elemental aluminum (Al) b) One hydrogen atom in H2O c) One oxygen atom in H20 d) Elemental hydrogen (H) e) One aluminum atom in Al(OH)4-1 f) One oxygen atom in Al(OH)4-1 g) One hydrogen atom in Al(OH)4-1

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  1. aaronq
    • 2 years ago
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    oxidation state on homonuclear molecules or elemental species = 0

  2. aaronq
    • 2 years ago
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    Oxygen = -2 always

  3. aaronq
    • 2 years ago
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    you can figure out the rest by balancing the charges

  4. bowlinL7252
    • 2 years ago
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    Alright, so for a i got 0, b -3, c -2, d 1, e 2, f -2 and g 0. Are these right?

  5. Frostbite
    • 2 years ago
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    Let me see if I get this right: You suggest that hydrogen in water have the oxidation number -3?

  6. bowlinL7252
    • 2 years ago
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    I believe so

  7. Frostbite
    • 2 years ago
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    Okay. We need an additional rule: "The sum of oxidations numbers most equal to total charge of the molecule." So when we look at water it have no charge... sense oxygen always get -2 each hydrogen most be what?

  8. bowlinL7252
    • 2 years ago
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    -5? And in that equation, which element was reduced and which was oxidized?

  9. bowlinL7252
    • 2 years ago
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    And can verify my answers please?

  10. Frostbite
    • 2 years ago
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    Best you get some training, so I'm gonna start with water and we take them each by each. H2O we take notice: Total charge = 0 oxygen always -2 Hydrogen always +1 This also make sense we should say: 0=-2+2*x <-> x=+1

  11. Frostbite
    • 2 years ago
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    aluminum is right. again it does not have charge and is an elemental species.

  12. bowlinL7252
    • 2 years ago
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    Both hydrogens are positive one as well?

  13. Frostbite
    • 2 years ago
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    Yes. it is 2 times +1

  14. bowlinL7252
    • 2 years ago
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    Alright, so what about for e through g?

  15. bowlinL7252
    • 2 years ago
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    hello?

  16. Frostbite
    • 2 years ago
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    Sorry I was thinking. both e and g are wrong.

  17. Frostbite
    • 2 years ago
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    The oxidation state of oxygen is -2 the oxidation state of hydrogen is +1: so we get: Al(OH)4 -1 -1 = -8+4+x Here is x the oxidation state of Al.. What is x?

  18. Frostbite
    • 2 years ago
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    Not quite.

  19. Frostbite
    • 2 years ago
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    \[-1=-8+4+x\] \[x=-1+8-4=3\]

  20. bowlinL7252
    • 2 years ago
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    So aluminum was reduced, so which was oxidized?

  21. aaronq
    • 2 years ago
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    which one are you working on?

  22. bowlinL7252
    • 2 years ago
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    g

  23. bowlinL7252
    • 2 years ago
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    I need the answer for g and then: In the equation above, which element was reduced and which element was oxidized?

  24. aaronq
    • 2 years ago
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    The H on the compound is part of the hydroxide ion, which is OH^- since O is -2 and theres a -1 charge on ion, H is +1

  25. bowlinL7252
    • 2 years ago
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    Awesome. so then which was oxidized and which was reduced?

  26. aaronq
    • 2 years ago
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    they're both 0 when not part of a molecule, if one gains e then we say its reduced because it became more negative, the opposite is for oxidized.

  27. bowlinL7252
    • 2 years ago
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    I mean for all of the elements in the equations, it seems like aluminum gained electrons

  28. bowlinL7252
    • 2 years ago
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    !

  29. aaronq
    • 2 years ago
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    we already did everything in the equation

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