Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Hi guys, one question with a couple of parts! What is the oxidation state for the atoms in the reaction: 2Al + 8H2O → 2H+1 + 3H2 + 2Al(OH)4-1 a) Elemental aluminum (Al) b) One hydrogen atom in H2O c) One oxygen atom in H20 d) Elemental hydrogen (H) e) One aluminum atom in Al(OH)4-1 f) One oxygen atom in Al(OH)4-1 g) One hydrogen atom in Al(OH)4-1

Chemistry
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
oxidation state on homonuclear molecules or elemental species = 0
Oxygen = -2 always
you can figure out the rest by balancing the charges

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Alright, so for a i got 0, b -3, c -2, d 1, e 2, f -2 and g 0. Are these right?
Let me see if I get this right: You suggest that hydrogen in water have the oxidation number -3?
I believe so
Okay. We need an additional rule: "The sum of oxidations numbers most equal to total charge of the molecule." So when we look at water it have no charge... sense oxygen always get -2 each hydrogen most be what?
-5? And in that equation, which element was reduced and which was oxidized?
And can verify my answers please?
Best you get some training, so I'm gonna start with water and we take them each by each. H2O we take notice: Total charge = 0 oxygen always -2 Hydrogen always +1 This also make sense we should say: 0=-2+2*x <-> x=+1
aluminum is right. again it does not have charge and is an elemental species.
Both hydrogens are positive one as well?
Yes. it is 2 times +1
Alright, so what about for e through g?
hello?
Sorry I was thinking. both e and g are wrong.
The oxidation state of oxygen is -2 the oxidation state of hydrogen is +1: so we get: Al(OH)4 -1 -1 = -8+4+x Here is x the oxidation state of Al.. What is x?
Not quite.
\[-1=-8+4+x\] \[x=-1+8-4=3\]
So aluminum was reduced, so which was oxidized?
which one are you working on?
g
I need the answer for g and then: In the equation above, which element was reduced and which element was oxidized?
The H on the compound is part of the hydroxide ion, which is OH^- since O is -2 and theres a -1 charge on ion, H is +1
Awesome. so then which was oxidized and which was reduced?
they're both 0 when not part of a molecule, if one gains e then we say its reduced because it became more negative, the opposite is for oxidized.
I mean for all of the elements in the equations, it seems like aluminum gained electrons
!
we already did everything in the equation

Not the answer you are looking for?

Search for more explanations.

Ask your own question