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u0860867

  • one year ago

Urgent help needed pls help

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  1. u0860867
    • one year ago
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  2. AravindG
    • one year ago
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    Divide whole equation by 2

  3. u0860867
    • one year ago
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    @UnkleRhaukus @terenzreignz do u guys have an idea of how to solve this

  4. UnkleRhaukus
    • one year ago
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    well i can think of an angle; that simultaneously makes the sin function equal one , and the cosine function equal to zero

  5. u0860867
    • one year ago
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    @UnkleRhaukus is that 90

  6. UnkleRhaukus
    • one year ago
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    yeahs that is one solution

  7. UnkleRhaukus
    • one year ago
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    i think there is one more solution

  8. u0860867
    • one year ago
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    -270 @UnkleRhaukus

  9. UnkleRhaukus
    • one year ago
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    that angle would solve the equation, however it is not in the correct domain

  10. u0860867
    • one year ago
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    idk what the other angle is then @UnkleRhaukus

  11. u0860867
    • one year ago
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    @terenzreignz @unkleRhukus if u guys could help me i would be greatful

  12. RadEn
    • one year ago
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    convert asinx + bcosx to kcos(x - θ) with k = sqrt(a^2 + b^2), also to get θ use tanθ = b/a

  13. RadEn
    • one year ago
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    i mean tanθ = a/b :)

  14. u0860867
    • one year ago
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    thanks @RadEn do you think you could help me with other questions

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