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AravindG Group TitleBest ResponseYou've already chosen the best response.0
Divide whole equation by 2
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
@UnkleRhaukus @terenzreignz do u guys have an idea of how to solve this
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
well i can think of an angle; that simultaneously makes the sin function equal one , and the cosine function equal to zero
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
@UnkleRhaukus is that 90
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
yeahs that is one solution
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
i think there is one more solution
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
270 @UnkleRhaukus
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
that angle would solve the equation, however it is not in the correct domain
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
idk what the other angle is then @UnkleRhaukus
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
@terenzreignz @unkleRhukus if u guys could help me i would be greatful
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
convert asinx + bcosx to kcos(x  θ) with k = sqrt(a^2 + b^2), also to get θ use tanθ = b/a
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
i mean tanθ = a/b :)
 one year ago

u0860867 Group TitleBest ResponseYou've already chosen the best response.0
thanks @RadEn do you think you could help me with other questions
 one year ago
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