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iplayffxiv

  • 2 years ago

find the derivative

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  1. iplayffxiv
    • 2 years ago
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    \[\frac{ d }{ dx }\int\limits_{0}^{x ^{3}}\sin t dt\]

  2. dumbcow
    • 2 years ago
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    \[=\frac{d}{dx} [-\cos(x^{3})-(-\cos(0))]\] \[= \frac{d}{dx} 1-\cos(x^{3})\] \[= 3x^{2} \sin(x^{3})\]

  3. iplayffxiv
    • 2 years ago
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    seems right to me. are you sure?

  4. dumbcow
    • 2 years ago
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    yes http://www.wolframalpha.com/input/?i=differentiate+integral+sin%28t%29+dt+from+0+to+x%5E3

  5. iplayffxiv
    • 2 years ago
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    i could not figure out how to type those limits in wolfram

  6. iplayffxiv
    • 2 years ago
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    so i had to ask it here

  7. iplayffxiv
    • 2 years ago
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    thanks

  8. dumbcow
    • 2 years ago
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    ahh ok ....yw

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