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x(t) may be positive and negative so simply doing x(3) - x(1) may not work

I DON'T GET THISSSS

the total distance traveled may not be the distance between x(1) and x(3)

Okay, thank you.

Ok, guide her steps, please

Okay. I got that much now.

so the first step is to set v(t) equal to zero?

Indeed

Okay..

What am I trying to get out of setting it to zero? Like do I basically un-FOIL it?

basically yes use whatever method you know to solve quadratic equations

erm alright. Thanks hold on :)

by setting it to zero

by setting to zero you are telling the equation that the particle is at rest

Okay, That i can actually understand. So what is it after you equal it to zero

I don't understand what you put in parenthesis.

I said that you may be able to solve the equation now that we divided by 3?

Yes. is it 3(t-2)(t-4) ?

yes, there is no need for the three as the other side is equal to 0 as 0/3=0

Okay.. so where in the equation (t-2)(t-4) do I get my answer? What am I taking from it? The zeros?

if (t-2)(t-4)=0 imagine a times b =0 how do we get that?
what is a or b?

Like the zeros being 2 and 4? I don't understand what I'm trying to get from this equation

the solution is that either A or B HAASSS to equal 0 so, t-2=0 or t-4 =0 such t=2 and 4

Okay, that's what I was thinking.

So t=2 and t=4 are the values for the particles at rest because thats the values where t=0. Correct?

yes but a typo on your end is you want v=0 at the end

That's what I meant :P How do I do B?

so you have an eqaution for the distance from 0 in terms of t, how would you approach it? any ideas?

its ok, when I first had answered I thought you had basic calculus but no problem, from part a you know that its stationary at t=2 and 4 so in the time period 1->3 the particle must change direction

Okay. Got it.

Yes.

How do we find the distance? Will the second equation be used?

Okay. How do you find the distance between the two?

x(1)= put 1 into to t of x(t)

Thank you so much. I appreciate it very very very much :)

Uh.. Thank you..

ok

I already knew that.

The answer is 6 units.

No, it isn't.