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What would be the following system of equations looks like and augmented Matrix? x+y=5 3x+y=-1

Mathematics
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what does your work look like?
I haven't done any, I was coming to look for help before I did anything, I don't wanna screw it up.
you have to "screw it up" in order to learn it better

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Other answers:

pull off the coeffs, and run your row operations ...
Awww, work darn. I don't have any. I know the answer to the X and Y is (1,4)
the the augment will have to end in a column of 1 4
None have "1,4" its all 3 -1 0 5
assuming youve got the correct 1,4 solution, the augment will have to work out as x+y=5 3x+y=-1 1 1 5 1 0 1 3 1 -1 to 0 1 4
What were those links for?
The Answers.
to be more exact ... the "options"
Yea Options
the solution of Ax = b (A:b) -> ( I : x)
I think I got the "answer" |dw:1368457593989:dw|
that is not an augment ....
hmm
Let me ask my mom and ill come back if she can't explain it's easier if i can actually see the work being done
and your links are not effective ....
It's because CA locked them -_-
How could (1,4) be a solution of 3x + y = -1 ?
magic ::)
It is.
I know it @amistre64 |dw:1368457855932:dw|
that is the start of the augment, yes
Well, you have three mods on the case, you can't possibly go wrong now :D
Well I am not really good in matrix, nor algebra. So I need all the help I can get.
assuming: 3x - y = -1 was part of the question
Yes
that is the matrix to augment, but is not the augmented matrix yet
1 thing why am I learning matrix in 9th grade?
because they are important
But isn't that 11th and 12th grade stuff?
apparently not :)
Gawdddddd well ok back to the subject
there are 3 basic methods to solving systems of equations: substitution elimination matrix row operations matrix row operations are really just a combination of the other 2
I was thinking Substitution since I know it better
substitution is not ideal for most situations ... its only effective on the hand picked easy peasy things they give you to practice on
Ohhhh ok :D
I figure if you can do elimination, Matrix Row Operations shouldn't be a problem, it's essentially the same thing, without the variables...
most solutions to real world problems require a computer to work on them, and the row operations are better suited to optimize a computers functionality
Ok can we explain to the imbecile (me) how to do so?
row operations are pretty much the elimination method x + y = 5 : *-3 3x - y = -1 -3x -3y = -15 3x - y = -1 ------------- 0x -4y = -16 x + y = 5 0x -4y = -16 : /-4 x + y = 5 0x + y = 4 : * -1 x + y = 5 0x - y = -4 ----------- x + 0y = 1 x+0y = 1 0x + y = 4
a matrix is a way to organize the same setup without the rest of the notation getting in the way
Mother of details o.O
Ok i see now :D
it takes some practice, but its fine :) good luck
I will take that too go :D thank you times a million @amistre64
Thank you too @terenzreignz
I hardly did anything, but okay, no problem :)
It's fine at least you helped I would medal you too but i cant D: -gives medal- internet medal :D
LOL Thanks :)
wat are the answers though im in connections academy

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