Notamathgenius
What would be the following system of equations looks like and augmented Matrix?
x+y=5
3x+y=-1
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amistre64
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what does your work look like?
Notamathgenius
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I haven't done any, I was coming to look for help before I did anything, I don't wanna screw it up.
amistre64
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you have to "screw it up" in order to learn it better
amistre64
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pull off the coeffs, and run your row operations ...
Notamathgenius
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Awww, work darn. I don't have any. I know the answer to the X and Y is (1,4)
amistre64
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the the augment will have to end in a column of 1 4
Notamathgenius
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None have "1,4" its all 3 -1 0 5
amistre64
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assuming youve got the correct 1,4 solution, the augment will have to work out as
x+y=5
3x+y=-1
1 1 5 1 0 1
3 1 -1 to 0 1 4
terenzreignz
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What were those links for?
Notamathgenius
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The Answers.
amistre64
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to be more exact ... the "options"
Notamathgenius
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Yea Options
amistre64
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the solution of Ax = b
(A:b) -> ( I : x)
Notamathgenius
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I think I got the "answer" |dw:1368457593989:dw|
amistre64
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that is not an augment ....
Notamathgenius
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hmm
Notamathgenius
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Let me ask my mom and ill come back if she can't explain it's easier if i can actually see the work being done
amistre64
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and your links are not effective ....
Notamathgenius
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It's because CA locked them -_-
terenzreignz
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How could (1,4) be a solution of 3x + y = -1 ?
amistre64
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magic ::)
Notamathgenius
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It is.
Notamathgenius
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I know it @amistre64 |dw:1368457855932:dw|
amistre64
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that is the start of the augment, yes
terenzreignz
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Well, you have three mods on the case, you can't possibly go wrong now :D
Notamathgenius
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Well I am not really good in matrix, nor algebra. So I need all the help I can get.
amistre64
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assuming: 3x - y = -1 was part of the question
Notamathgenius
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Yes
amistre64
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that is the matrix to augment, but is not the augmented matrix yet
Notamathgenius
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1 thing
why am I learning matrix in 9th grade?
amistre64
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because they are important
Notamathgenius
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But isn't that 11th and 12th grade stuff?
amistre64
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apparently not :)
Notamathgenius
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Gawdddddd
well ok back to the subject
amistre64
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there are 3 basic methods to solving systems of equations:
substitution
elimination
matrix row operations
matrix row operations are really just a combination of the other 2
Notamathgenius
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I was thinking Substitution since I know it better
amistre64
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substitution is not ideal for most situations ... its only effective on the hand picked easy peasy things they give you to practice on
Notamathgenius
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Ohhhh ok :D
terenzreignz
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I figure if you can do elimination, Matrix Row Operations shouldn't be a problem, it's essentially the same thing, without the variables...
amistre64
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most solutions to real world problems require a computer to work on them, and the row operations are better suited to optimize a computers functionality
Notamathgenius
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Ok can we explain to the imbecile (me) how to do so?
amistre64
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row operations are pretty much the elimination method
x + y = 5 : *-3
3x - y = -1
-3x -3y = -15
3x - y = -1
-------------
0x -4y = -16
x + y = 5
0x -4y = -16 : /-4
x + y = 5
0x + y = 4 : * -1
x + y = 5
0x - y = -4
-----------
x + 0y = 1
x+0y = 1
0x + y = 4
amistre64
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a matrix is a way to organize the same setup without the rest of the notation getting in the way
terenzreignz
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Mother of details o.O
Notamathgenius
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Ok i see now :D
amistre64
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it takes some practice, but its fine :) good luck
Notamathgenius
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I will take that too go :D thank you times a million @amistre64
Notamathgenius
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Thank you too @terenzreignz
terenzreignz
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I hardly did anything, but okay, no problem :)
Notamathgenius
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It's fine at least you helped I would medal you too but i cant D: -gives medal- internet medal :D
terenzreignz
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LOL Thanks :)
youngling88
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wat are the answers though im in connections academy