## Notamathgenius 2 years ago What would be the following system of equations looks like and augmented Matrix? x+y=5 3x+y=-1

1. amistre64

what does your work look like?

2. Notamathgenius

I haven't done any, I was coming to look for help before I did anything, I don't wanna screw it up.

3. amistre64

you have to "screw it up" in order to learn it better

4. amistre64

pull off the coeffs, and run your row operations ...

5. Notamathgenius

Awww, work darn. I don't have any. I know the answer to the X and Y is (1,4)

6. amistre64

the the augment will have to end in a column of 1 4

7. Notamathgenius

None have "1,4" its all 3 -1 0 5

8. amistre64

assuming youve got the correct 1,4 solution, the augment will have to work out as x+y=5 3x+y=-1 1 1 5 1 0 1 3 1 -1 to 0 1 4

9. terenzreignz

10. Notamathgenius

11. amistre64

to be more exact ... the "options"

12. Notamathgenius

Yea Options

13. amistre64

the solution of Ax = b (A:b) -> ( I : x)

14. Notamathgenius

I think I got the "answer" |dw:1368457593989:dw|

15. amistre64

that is not an augment ....

16. Notamathgenius

hmm

17. Notamathgenius

Let me ask my mom and ill come back if she can't explain it's easier if i can actually see the work being done

18. amistre64

19. Notamathgenius

It's because CA locked them -_-

20. terenzreignz

How could (1,4) be a solution of 3x + y = -1 ?

21. amistre64

magic ::)

22. Notamathgenius

It is.

23. Notamathgenius

I know it @amistre64 |dw:1368457855932:dw|

24. amistre64

that is the start of the augment, yes

25. terenzreignz

Well, you have three mods on the case, you can't possibly go wrong now :D

26. Notamathgenius

Well I am not really good in matrix, nor algebra. So I need all the help I can get.

27. amistre64

assuming: 3x - y = -1 was part of the question

28. Notamathgenius

Yes

29. amistre64

that is the matrix to augment, but is not the augmented matrix yet

30. Notamathgenius

1 thing why am I learning matrix in 9th grade?

31. amistre64

because they are important

32. Notamathgenius

But isn't that 11th and 12th grade stuff?

33. amistre64

apparently not :)

34. Notamathgenius

Gawdddddd well ok back to the subject

35. amistre64

there are 3 basic methods to solving systems of equations: substitution elimination matrix row operations matrix row operations are really just a combination of the other 2

36. Notamathgenius

I was thinking Substitution since I know it better

37. amistre64

substitution is not ideal for most situations ... its only effective on the hand picked easy peasy things they give you to practice on

38. Notamathgenius

Ohhhh ok :D

39. terenzreignz

I figure if you can do elimination, Matrix Row Operations shouldn't be a problem, it's essentially the same thing, without the variables...

40. amistre64

most solutions to real world problems require a computer to work on them, and the row operations are better suited to optimize a computers functionality

41. Notamathgenius

Ok can we explain to the imbecile (me) how to do so?

42. amistre64

row operations are pretty much the elimination method x + y = 5 : *-3 3x - y = -1 -3x -3y = -15 3x - y = -1 ------------- 0x -4y = -16 x + y = 5 0x -4y = -16 : /-4 x + y = 5 0x + y = 4 : * -1 x + y = 5 0x - y = -4 ----------- x + 0y = 1 x+0y = 1 0x + y = 4

43. amistre64

a matrix is a way to organize the same setup without the rest of the notation getting in the way

44. terenzreignz

Mother of details o.O

45. Notamathgenius

Ok i see now :D

46. amistre64

it takes some practice, but its fine :) good luck

47. Notamathgenius

I will take that too go :D thank you times a million @amistre64

48. Notamathgenius

Thank you too @terenzreignz

49. terenzreignz

I hardly did anything, but okay, no problem :)

50. Notamathgenius

It's fine at least you helped I would medal you too but i cant D: -gives medal- internet medal :D

51. terenzreignz

LOL Thanks :)

52. youngling88