anonymous
  • anonymous
Medal to first who explains me this question :) Find the roots of the equation (comment).
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
\[x ^{3}-x ^{2}-7x+3\]
anonymous
  • anonymous
k whats the question
anonymous
  • anonymous
ok do you want it factorized or what?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
That's problem, I'm not quite sure what should I do :s
anonymous
  • anonymous
x^3+x^2-7x-3 One of the roots is x(1) = -3 After applying Polynomial remainder theorem you will have a second order equation x^2 - 2x - 1 = 0 a = 1 ; b = -2 ; c = -1 x(2,3) = (-b)(+/-)SqRoot{b^2 - 4 . a . c}/(2 a)= x(2,3) = (2)(+/-)SqRoot{4 - 4 . 1 . (-1)}/(2 . 1)= x(2,3) = (2)(+/-)SqRoot{4 + 4}/(2)= x(2,3) = 2 (+/-) SqRoot { 8 } / 2 = x(2,3) = 1 (+/-) SqRoot { 2 } ---> x(2) = 1 + SqRoot { 2 } ---> x(3) = 1 - SqRoot { 2 }
anonymous
  • anonymous
u should do that but instead of doing minus you do the addition this was a mere example but close enough so that you would know what to do
anonymous
  • anonymous
I understand second part perfectly that's not problem :) can you just explain how did you get -3 as one of the roots? I'm bit confused
anonymous
  • anonymous
I just replaced +3 with -3 in this example
anonymous
  • anonymous
so in your case the root would be +3
anonymous
  • anonymous
Why is that?
anonymous
  • anonymous
capish? :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.