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Medal to first who explains me this question :)
Find the roots of the equation (comment).
 11 months ago
 11 months ago
Medal to first who explains me this question :) Find the roots of the equation (comment).
 11 months ago
 11 months ago

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nickersiaBest ResponseYou've already chosen the best response.0
\[x ^{3}x ^{2}7x+3\]
 11 months ago

shelbygt520Best ResponseYou've already chosen the best response.1
k whats the question
 11 months ago

shelbygt520Best ResponseYou've already chosen the best response.1
ok do you want it factorized or what?
 11 months ago

nickersiaBest ResponseYou've already chosen the best response.0
That's problem, I'm not quite sure what should I do :s
 11 months ago

shelbygt520Best ResponseYou've already chosen the best response.1
x^3+x^27x3 One of the roots is x(1) = 3 After applying Polynomial remainder theorem you will have a second order equation x^2  2x  1 = 0 a = 1 ; b = 2 ; c = 1 x(2,3) = (b)(+/)SqRoot{b^2  4 . a . c}/(2 a)= x(2,3) = (2)(+/)SqRoot{4  4 . 1 . (1)}/(2 . 1)= x(2,3) = (2)(+/)SqRoot{4 + 4}/(2)= x(2,3) = 2 (+/) SqRoot { 8 } / 2 = x(2,3) = 1 (+/) SqRoot { 2 } > x(2) = 1 + SqRoot { 2 } > x(3) = 1  SqRoot { 2 }
 11 months ago

shelbygt520Best ResponseYou've already chosen the best response.1
u should do that but instead of doing minus you do the addition this was a mere example but close enough so that you would know what to do
 11 months ago

nickersiaBest ResponseYou've already chosen the best response.0
I understand second part perfectly that's not problem :) can you just explain how did you get 3 as one of the roots? I'm bit confused
 11 months ago

shelbygt520Best ResponseYou've already chosen the best response.1
I just replaced +3 with 3 in this example
 11 months ago

shelbygt520Best ResponseYou've already chosen the best response.1
so in your case the root would be +3
 11 months ago
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