At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
Well you have to factor out a -5 from the second part to get the equations to match
Oh! It's because I did it like this: 5(-7v+1) and I still got the same answer
|dw:1368510657852:dw| If you got that when you factored then it would be wrong because the two equations are not the same. When factoring by grouping, equations have to be EXACTLY the same for it to work.
Unless you factored out a -2v^2..
Your factoring is correct in the sense that what you got is equal to the unfactored expression, but since there is no common factor you can't continue. The goal of factoring by groups is to get a common factor.
Yeah, I'm getting what you guys are saying now. My teacher said though that I am able to change the sign around to get it to match
If you are asked specifically to factor a polynomial by grouping, then chances are you are given a problem that can be factored by grouping. In this case, there will be a common factor that you can pull out. You just may have to adjust the sign of what you pull out to make sure what's left is equal to what was left in the first group.