anonymous
  • anonymous
16x²-8x+1=0
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
nathan917
  • nathan917
This a graph question?
anonymous
  • anonymous
2) 2x²-7x+3=0 3)2x²-x-6=0 4)9x²-3x-2=0 5)y²-6y+2=0 6)4x²-20x+25=0 7)4x²-7x-15=0
anonymous
  • anonymous
no its not they are solving quadratic equations all of them

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
you can solve it by one of the ways used for quadratic equations, like you can try it by using quadratic formula [x=b \pm \sqrt{b ^{2}-4ac}\div2a\]
anonymous
  • anonymous
i dont know how thats the problem
anonymous
  • anonymous
can someone help me with it or what
terenzreignz
  • terenzreignz
Thankfully, there is the quadratic formula... it's foolproof... you interested? :D
anonymous
  • anonymous
sure
terenzreignz
  • terenzreignz
Well, anytime you're ready, if you have a quadratic equation of the form \[\Large \color{red}ax^2 + \color{blue}bx +\color{green}c = 0\] Where, of course, a is not 0, then the solutions can be quickly obtained using this formula... \[\LARGE x = \frac{-\color{blue}b \pm \sqrt{\color{blue}b^2 - 4\color{red}a\color{green}c}}{2\color{red}a}\] follow this formula (carefully) and you can never go wrong with quadratic equations :D
terenzreignz
  • terenzreignz
Let's take the first one as an example... shall we? :)
anonymous
  • anonymous
okay
terenzreignz
  • terenzreignz
\[\Large \color{red}{16}x^2 -\color{blue}8x +\color{green}1 = 0 \] In this case, what are your values for a,b, and c?
anonymous
  • anonymous
a=15 b=8 and c=1
terenzreignz
  • terenzreignz
Where did you get a = 15? lol Also, note the minus-sign preceding the 8... better rethink your value for b.... With those said, what are the values for a,b, and c? :)
anonymous
  • anonymous
i meant 16 and -8 my fingers and laptop arennt behaving today as you can c
anonymous
  • anonymous
a=16 b=-8 c=1
terenzreignz
  • terenzreignz
LOL, it's fine :) So a = 16 b = -8 c = 1 Great :) So, we plug them into the quadratic formula... \[\LARGE x = \frac{-\color{blue}{(-8)}\pm \sqrt{\color{blue}{(-8)^2}- 4\color{red}{(16)}\color{green}{(1)}}}{2\color{red}{(16)}}\] And just solve :)
anonymous
  • anonymous
8+-sqrt 64+64/32
anonymous
  • anonymous
@terenzreignz i dont know exactly how to do this from here
terenzreignz
  • terenzreignz
Okay, relax.. deep breaths :D
anonymous
  • anonymous
lol terenz. dont be so dramatic XD
terenzreignz
  • terenzreignz
\[\LARGE x = \frac{\color{blue}{(8)}\pm \sqrt{\color{blue}{64}- \color{red}{64}}}{\color{red}{32}}\] Simplify. :)
anonymous
  • anonymous
8/32
terenzreignz
  • terenzreignz
simplify? :D
anonymous
  • anonymous
.25
anonymous
  • anonymous
so both answers are .25
terenzreignz
  • terenzreignz
Personally, I prefer 1/4, but whatever floats your boat :P
anonymous
  • anonymous
yay lol wanna keep helpin me i get the way you talk lol
terenzreignz
  • terenzreignz
I haven't said a word :D Okay, do the second one, I'll watch for errors :)
anonymous
  • anonymous
liar! lol 2x^2-7x+3 a=2 b=-7 c=3 whats the quadratic formula?
terenzreignz
  • terenzreignz
\[\LARGE x = \frac{-\color{blue}b \pm \sqrt{\color{blue}b^2 - 4\color{red}a\color{green}c}}{2\color{red}a}\]
anonymous
  • anonymous
okay so -2+-sqrt2^2-4(-7)(3)/2(2)
anonymous
  • anonymous
then simplify to get -2=-sqrt88/4 now what? @terenzreignz
terenzreignz
  • terenzreignz
Why -2? I thought b = -7 ?
anonymous
  • anonymous
shooot
anonymous
  • anonymous
okay hold on i got this
anonymous
  • anonymous
7+-sqrt25/4 thats right i know
terenzreignz
  • terenzreignz
Very good :) Now simplify.
anonymous
  • anonymous
thats the problem do i actually square it and what do i do with the 7????
anonymous
  • anonymous
i end up with .5 and 3 when i simplify
terenzreignz
  • terenzreignz
YOu got \[\Large \frac{7\pm \sqrt{25}}{4}\]
terenzreignz
  • terenzreignz
Which really means... \[\Large \frac{7+\sqrt5}{4} \quad and \quad \frac{7-\sqrt5}{4}\]
anonymous
  • anonymous
why square root of 5
terenzreignz
  • terenzreignz
whoops... sorry replace that with square root of 25 :)
anonymous
  • anonymous
ok so seven plus 5 and seven -5 divide both by four
terenzreignz
  • terenzreignz
Yup :) And those are your answers :D
anonymous
  • anonymous
3 and .5 i was right okay i need to do this one y^2-6y+2=0
anonymous
  • anonymous
so a= 1 b=-6 and c=2
terenzreignz
  • terenzreignz
Yes. Go ahead :D
anonymous
  • anonymous
6+5.2915/2=5.14575 6-5.2915/2=.35425
anonymous
  • anonymous
so 5.2 and.4
terenzreignz
  • terenzreignz
I wouldn't suggest approximating... leave it in radical form.
anonymous
  • anonymous
meaning
anonymous
  • anonymous
@terenzreignz
terenzreignz
  • terenzreignz
Meaning, leave it like this... \[\Large \frac{6\pm \sqrt{36-8}}{2}=\frac{6\pm \sqrt{28}}{2}=\frac{6\pm 2\sqrt7}{2}=3\pm\sqrt7\]
anonymous
  • anonymous
oh ok
terenzreignz
  • terenzreignz
I'm sure you can do the others now :)
anonymous
  • anonymous
whered 3 come from
terenzreignz
  • terenzreignz
We divided by 2 (to get rid of that denominator)
anonymous
  • anonymous
oh

Looking for something else?

Not the answer you are looking for? Search for more explanations.