anonymous
  • anonymous
A piece of art is in the shape of an equilateral triangle with sides of 6 in. Find the area of the piece of art. Round your answer to the nearest tenth.? A. 12.7 in.2 B. 15.6 in.2 C. 31.2 in.2 D. none of these
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
A=.5(B*H). B=3, H=6. A=.5(6*3)=9 in 2
anonymous
  • anonymous
A=.5(3*6)=9in^2 a=90
anonymous
  • anonymous
hey sorry let me explain it to u

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anonymous
  • anonymous
so area of triangle is .5*base*height right
anonymous
  • anonymous
we know our base, because we can divide 6 by 2 to get 3, but we dont know the height
anonymous
  • anonymous
so u need to use pythgorean thm. A^2+B^2=C^2
anonymous
  • anonymous
A being height. A^2+3^2=6^2
anonymous
  • anonymous
Solve for A, you will get 5.2
anonymous
  • anonymous
so A=.5*5.2*3=7.79
anonymous
  • anonymous
but now multiply by two because that is just half of the triangle, so its 15.6 in2
anonymous
  • anonymous
A is also area

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