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Notamathgenius

  • 2 years ago

write an equation in slope-intercept form of the line that passes through the given points (3, -2), (6,1) @ajprincess Same way?

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  1. ajprincess
    • 2 years ago
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    have u found the slope using that formula?

  2. Notamathgenius
    • 2 years ago
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    No c: i know nothing about slope intercept I dislike it a lot -_-

  3. ajprincess
    • 2 years ago
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    slope is found using the formula \[slope~m=\frac{y_2-y_1}{x_2-x_1}\] \[m=\frac{1-(-2)}{6-3}=?\]

  4. Notamathgenius
    • 2 years ago
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    i got -1.666666667

  5. ajprincess
    • 2 years ago
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    nw can u find m?

  6. ajprincess
    • 2 years ago
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    @notamathgenius

  7. Notamathgenius
    • 2 years ago
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    hmmm

  8. ajprincess
    • 2 years ago
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    sure?

  9. Notamathgenius
    • 2 years ago
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    Yea I am lost, i keep looking back at the question -_- grr i hate math

  10. ajprincess
    • 2 years ago
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    wht is 1-(-2)=?

  11. Notamathgenius
    • 2 years ago
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    3

  12. ajprincess
    • 2 years ago
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    good:) nw what is 6-3=?

  13. Notamathgenius
    • 2 years ago
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    3

  14. ajprincess
    • 2 years ago
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    good:) 3/3=?

  15. Notamathgenius
    • 2 years ago
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    1

  16. ajprincess
    • 2 years ago
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    good:) so what is m=?

  17. Notamathgenius
    • 2 years ago
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    1 :D

  18. ajprincess
    • 2 years ago
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    yup. good:)

  19. Notamathgenius
    • 2 years ago
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    Oh boy math is fun -_- not

  20. ajprincess
    • 2 years ago
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    nw let us consider a point (x.y) on the same line. then \[m=\frac{y-y_1}{x-x_1}\] \[1=\frac{y-(-2)}{x-3}\] \[1(x-3)=y+2\] Slope-intercept equation is \\[y=1(x-3)-2\]

  21. Notamathgenius
    • 2 years ago
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    I see now :) thanks a bunch

  22. ajprincess
    • 2 years ago
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    welcome:) remove the parentheses and simplify:)

  23. Notamathgenius
    • 2 years ago
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    WIll do :D

  24. ajprincess
    • 2 years ago
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    good:)

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