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ikoreanx3
Help! I need to show work for this question. 12b^-2-7b^-1+1=0
I got b = 4,3
\[\frac{ 12 }{ b^{2} }-\frac{ 7 }{ b }+1=0\] Multiply both sides by b^2 \[b^{2}-7b+12=0\] So your answer looks right.
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