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Haleyy_Bugg

  • one year ago

The graph of which quadratic equation is shown below? y = x^2 + 2x − 8 y = x^2 − 2x − 8 y = −x^2 − 2x + 8 y = −x^2 − 4x − 8

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  1. Haleyy_Bugg
    • one year ago
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  2. Haleyy_Bugg
    • one year ago
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    @Notamathgenius

  3. Notamathgenius
    • one year ago
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    Hmm not sure D:

  4. MathCurious
    • one year ago
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    Does the graph of x^2 open up or down? How about -x^2? :)

  5. cwrw238
    • one year ago
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    as its -x^2 it will be open downwards like C and D

  6. MathCurious
    • one year ago
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    f(x) + C will affect the position on the y axis. Take this fact into consideration.

  7. cwrw238
    • one year ago
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    yup the intercept on y-axis is when x = 0

  8. MathCurious
    • one year ago
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    |dw:1368631726428:dw| can you find the x -intercepts?

  9. MathCurious
    • one year ago
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    you should know the answer from this

  10. Haleyy_Bugg
    • one year ago
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    I dont

  11. MathCurious
    • one year ago
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    ok, set everything I drew above to zero, that is like saying: When is Y zero? When Y is zero it touches the x-axis

  12. MathCurious
    • one year ago
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    it is zero when x = 2 and when x = -4

  13. Haleyy_Bugg
    • one year ago
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    So the answer is...?

  14. MathCurious
    • one year ago
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    So then the answer is y = −x^2 − 2x + 8 I factored out the negative sign above.

  15. MathCurious
    • one year ago
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    look at your graph, it's consistent with this

  16. MathCurious
    • one year ago
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    Make sense? :)

  17. MathCurious
    • one year ago
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    lol, just looking for someone to do your homework without effort, eh?

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