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The graph of which quadratic equation is shown below?
y = x^2 + 2x − 8
y = x^2 − 2x − 8
y = −x^2 − 2x + 8
y = −x^2 − 4x − 8
 11 months ago
 11 months ago
The graph of which quadratic equation is shown below? y = x^2 + 2x − 8 y = x^2 − 2x − 8 y = −x^2 − 2x + 8 y = −x^2 − 4x − 8
 11 months ago
 11 months ago

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NotamathgeniusBest ResponseYou've already chosen the best response.0
Hmm not sure D:
 11 months ago

MathCuriousBest ResponseYou've already chosen the best response.0
Does the graph of x^2 open up or down? How about x^2? :)
 11 months ago

cwrw238Best ResponseYou've already chosen the best response.0
as its x^2 it will be open downwards like C and D
 11 months ago

MathCuriousBest ResponseYou've already chosen the best response.0
f(x) + C will affect the position on the y axis. Take this fact into consideration.
 11 months ago

cwrw238Best ResponseYou've already chosen the best response.0
yup the intercept on yaxis is when x = 0
 11 months ago

MathCuriousBest ResponseYou've already chosen the best response.0
dw:1368631726428:dw can you find the x intercepts?
 11 months ago

MathCuriousBest ResponseYou've already chosen the best response.0
you should know the answer from this
 11 months ago

MathCuriousBest ResponseYou've already chosen the best response.0
ok, set everything I drew above to zero, that is like saying: When is Y zero? When Y is zero it touches the xaxis
 11 months ago

MathCuriousBest ResponseYou've already chosen the best response.0
it is zero when x = 2 and when x = 4
 11 months ago

Haleyy_BuggBest ResponseYou've already chosen the best response.0
So the answer is...?
 11 months ago

MathCuriousBest ResponseYou've already chosen the best response.0
So then the answer is y = −x^2 − 2x + 8 I factored out the negative sign above.
 11 months ago

MathCuriousBest ResponseYou've already chosen the best response.0
look at your graph, it's consistent with this
 11 months ago

MathCuriousBest ResponseYou've already chosen the best response.0
lol, just looking for someone to do your homework without effort, eh?
 11 months ago
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