anonymous
  • anonymous
cos theta= - square root 2 divided by 2
Mathematics
jamiebookeater
  • jamiebookeater
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Mertsj
  • Mertsj
\[\cos \theta= -\frac{\sqrt{2}}{2}\]
anonymous
  • anonymous
yeah I need to solve the equation (0
Mertsj
  • Mertsj
We see that the cosine is negative. In what quadrants is the cosine negative?

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anonymous
  • anonymous
2 and 3
Mertsj
  • Mertsj
And on your unit circle, what angle has sqrt2/2 for its cosine?
anonymous
  • anonymous
-45
Mertsj
  • Mertsj
45 does have that cosine ut we said we would be in quadrants II and III where the cosine is negative. Also you said your answer had to be between 0 and 2 pi so I think you should give the answer in radians.
Mertsj
  • Mertsj
How many radians is 45 degrees?
anonymous
  • anonymous
45 degrees is pi/4
Mertsj
  • Mertsj
So...in quadrants II and III:
Mertsj
  • Mertsj
|dw:1368665856951:dw|
Mertsj
  • Mertsj
What is the angle meassured from the positive x axis?
anonymous
  • anonymous
135
Mertsj
  • Mertsj
radians, my dear.
anonymous
  • anonymous
3pi/4
Mertsj
  • Mertsj
Yes. And now for the third quadrant answer:
anonymous
  • anonymous
5pi/4
Mertsj
  • Mertsj
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Mertsj
  • Mertsj
Very good. And now you have your two answers. The angles between 0 and 2 pi that have a cosine of -sqrt2/2 are 3pi/4 and 5pi/4
anonymous
  • anonymous
perfect

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