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cos theta= - square root 2 divided by 2

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\[\cos \theta= -\frac{\sqrt{2}}{2}\]
yeah I need to solve the equation (0
We see that the cosine is negative. In what quadrants is the cosine negative?

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Other answers:

2 and 3
And on your unit circle, what angle has sqrt2/2 for its cosine?
45 does have that cosine ut we said we would be in quadrants II and III where the cosine is negative. Also you said your answer had to be between 0 and 2 pi so I think you should give the answer in radians.
How many radians is 45 degrees?
45 degrees is pi/4 quadrants II and III:
What is the angle meassured from the positive x axis?
radians, my dear.
Yes. And now for the third quadrant answer:
Very good. And now you have your two answers. The angles between 0 and 2 pi that have a cosine of -sqrt2/2 are 3pi/4 and 5pi/4

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