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cos theta= - square root 2 divided by 2

Mathematics
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\[\cos \theta= -\frac{\sqrt{2}}{2}\]
yeah I need to solve the equation (0
We see that the cosine is negative. In what quadrants is the cosine negative?

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Other answers:

2 and 3
And on your unit circle, what angle has sqrt2/2 for its cosine?
-45
45 does have that cosine ut we said we would be in quadrants II and III where the cosine is negative. Also you said your answer had to be between 0 and 2 pi so I think you should give the answer in radians.
How many radians is 45 degrees?
45 degrees is pi/4
So...in quadrants II and III:
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What is the angle meassured from the positive x axis?
135
radians, my dear.
3pi/4
Yes. And now for the third quadrant answer:
5pi/4
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Very good. And now you have your two answers. The angles between 0 and 2 pi that have a cosine of -sqrt2/2 are 3pi/4 and 5pi/4
perfect

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