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Please help? George is comparing three investment accounts offering different rates. Account A: APR of 3.75 compounding monthly Account B APR of 3.85 compounding quarterly Account C APR of 3.95 compounding daily Which account will give George at least a 4% annual yield?

Mathematics
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you need to compute three numbers \[(1+\frac{.0375}{4})^4\] \[(1+\frac{.0385}{12})^{12}\] \[(1+\frac{.0395}{365})^{365}\]
so which ever equals at least "4" will give me the answer then?
each will look like \(1+.0somthing\) choose the one or ones with the something greater than or equal to 4

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Other answers:

none will give you 4 if the answer looks like \(1.04...\) then that is a yield of larger than \(4\%\) if the answer is \(1.03...\) then no
wait the first two equations are mixed up am i right?
oh yeah my fault, sorry
\[(1+\frac{.0375}{12})^{12}\]
it's quite alright. I know how to set up the problem now. but about the yeild, the number won't equal 4, but if the last digit in the number is greater than or equal to 4 than that is the answer i would choose?
\[(1+\frac{.0385}{4})^{4}\] good catch
lets compute one
here is the first one http://www.wolframalpha.com/input/?i=%281%2B.0375%2F12%29^12
you can see that the answer is \[1.033815...\]
so that one can be ruled out
so this one is out since it is smaller than \(1.04\)
right
I'll try the second one..
ok you can edit the one i did to compute it if you like
is the little 4 on the outside an exponent?
yes, that needs to be a 4, and also the denominator under \(.0385\) should be a 4 also
1.039 is what it gave me
me too
it is the last one, it gave me 1.04
then i guess that is the one you want
thanks for the help
you good with this?
yw
yes indeed :3

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