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i got 49/4 is that correct?

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Other answers:

I don't get why your pics are so small, please make them bigger if possible. Or just actually write it yourself like so... I'm going to write this so people can actually read it: \[\Large \int\limits_{0}^{2} x \sqrt{ 4x^2 +9} dx\]
okay
yea thats correct
As long as you used u substitution with u=4x^2+9, du= 8x dx, it should be correct. 49/4 isn't correct, but it's close.
okay i tried again and i got 49/6
http://www.wolframalpha.com/input/?i=%5Cint%5Climits_%7B0%7D%5E%7B2%7D+x++%5Csqrt%7B+4x%5E2+%2B9%7D+dx
okay so my question has multiple choices and in them none of that has 49/6
there is 32/3, 15/4, 80/9 and 49/4
Mathematica returned 49/6
yea i'm guessing my teacher made a mistake
Refer to the attachment
1 Attachment
@robtobey I already posted the wolfram alpha solution... which uses mathematica :P
Sorry about that.

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