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emilyr123

4sin(theta)+3sqrt3=sqrt3 solve w/ interval 0 < theta < 2pi

  • 11 months ago
  • 11 months ago

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  1. psi9epsilon
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    Pretty straightforward \[4 \sin (\theta) = \sqrt{3} - 3\sqrt{3}\]

    • 11 months ago
  2. psi9epsilon
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    \[4\sin (\theta)=-2\sqrt{3}\]

    • 11 months ago
  3. psi9epsilon
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    \[\sin (\theta)=-2\sqrt{3 } / 4\]

    • 11 months ago
  4. psi9epsilon
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    \[\sin (\theta)=-\sqrt{3} / 2\]

    • 11 months ago
  5. psi9epsilon
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    \[\theta = \sin^{-1} (-\sqrt{3}/2)\]

    • 11 months ago
  6. psi9epsilon
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    sin THETA is NEGATIVE only in 3rd and 4th quadrant

    • 11 months ago
  7. psi9epsilon
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    \[\theta=\sin^{-1} (\sin(\pi+\pi/3))\]

    • 11 months ago
  8. psi9epsilon
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    THETA = 4 PI /3

    • 11 months ago
  9. psi9epsilon
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    OR THETA = 2PI - PI/3 = 5PI/3

    • 11 months ago
  10. psi9epsilon
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    TWO ANSWERS as the interval is from 0 -> 2 Pi

    • 11 months ago
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