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mathslover
 one year ago
Best ResponseYou've already chosen the best response.0It is easy , it just looks long. I will do that after lunch, ok?

DLS
 one year ago
Best ResponseYou've already chosen the best response.1\[\Huge \lim_{x \rightarrow 0}( \frac{1}{x} \int\limits_{0}^{a} e^{\sin^{2}t}dt\int\limits_{x+y}^{a} e^{\sin^{2}t}dt)\]

DLS
 one year ago
Best ResponseYou've already chosen the best response.1Okay @mathslover and I know it is easy,I was trying it but i think the first term will cancel off because a and y both are constants maybe..i can be wrong,just drop a hint.

DLS
 one year ago
Best ResponseYou've already chosen the best response.1sorry the term 1/x is outside everything

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2we can write the expression as.... (first term) + ∫ e^(sin^2 t dt) with limits ... a to x+y.. the sign changed on reversing the limits..

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2now combining the two limits.. 0 to a and a to x+y .. 0 to x+y ..

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2because the integrand is same..

DLS
 one year ago
Best ResponseYou've already chosen the best response.10 to a and 0 to x+y=0 to x+y

DLS
 one year ago
Best ResponseYou've already chosen the best response.1\[\Huge \frac{1}{x} e^{\sin^{2}x+y}\]

DLS
 one year ago
Best ResponseYou've already chosen the best response.1differenatiate and bingo :O

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2why did you not do anything to 1/x ?

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2multiplication theorem.. hmm..

DLS
 one year ago
Best ResponseYou've already chosen the best response.11/x was outside the integral sorry :P

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2aur jab 0 put krenge.. to bhi to kuch aayega. vo kahan gyi? :P

DLS
 one year ago
Best ResponseYou've already chosen the best response.1\[\Huge \lim_{x \rightarrow 0} \frac{1}{x}(\int\limits_{y}^{a}e^{\sin^{2}t} dt\int\limits_{x+y}^{a}e^{\sin^{2}t} dt)\]

DLS
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large \lim_{x \rightarrow 0} \frac{1}{x}(\int\limits_{y}^{x+y}e^{\sin^{2}t} dt)\] On changing the sign and revevrsing the limits and combining them

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2acha vo 'a' vala to 0 ho jayega.. a ki differentiation 0.. but hamne x+y ko differentiate bhi nhi kra.. :/

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.0kya hua? kya dikkat hai ? (:

DLS
 one year ago
Best ResponseYou've already chosen the best response.1\[\Huge e^{\sin^{2}{x+y}}(1+\frac{dy}{dx})e^{\sin^{2}y} \frac{dy}{dx}\]

DLS
 one year ago
Best ResponseYou've already chosen the best response.1\[\Huge e^{\sin^{2}x+y}\] answer

DLS
 one year ago
Best ResponseYou've already chosen the best response.1y is behaving as a constant,we assume y independent of x

DLS
 one year ago
Best ResponseYou've already chosen the best response.1idk what i wrote please someone explain :P

DLS
 one year ago
Best ResponseYou've already chosen the best response.1If we are driving a car and chasing a thief on a bike then the rate of change of our speed won't affect the speed of the theif's bike

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2limit y se x+y ?? how??

DLS
 one year ago
Best ResponseYou've already chosen the best response.1\[\LARGE e^{\sin^{2}x+y}\] differentiating this^

DLS
 one year ago
Best ResponseYou've already chosen the best response.1\[\LARGE e^{\sin^{2}x+y} \times \sin2x(+0)\]

DLS
 one year ago
Best ResponseYou've already chosen the best response.1\[\LARGE e^{\sin^{2}y}\] Differentiating the lower limit^

DLS
 one year ago
Best ResponseYou've already chosen the best response.1\[\LARGE e^{\sin^{2}y}=>e^{\sin^{2}y} \times \sin2y\]

DLS
 one year ago
Best ResponseYou've already chosen the best response.1I'm left with.. \[\LARGE \frac{1}{x}e^{\sin^{2}x+y} \times \sin2x\]

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2abbe yr. x ki differentiation 1 hogi.. LH me numerator aur denominator alag alag diff krte hain.. :/

DLS
 one year ago
Best ResponseYou've already chosen the best response.1maine bhi to wahi bola tha BC

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2to x ki diff 1 ho jayegi.. aur numerator me tune jo kra tha. dy/dx=0 krke aa jayega ans.

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2kya 1 ka 0? 1 baari diff krenge.. :/

DLS
 one year ago
Best ResponseYou've already chosen the best response.11/x hai to 1 ka karenge to 0 x ka karenge to 1 0/1=0

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2lol. 1*x ki diff. 0*x + 1*1.. lol

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2to upar sirf 1 thodi hai.. baaki bhi to hai. usse multiply krega saara.. to 1* ....... = ......... aa jayega.. :O

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2newton lebinitz me integrand ki differentiation nhi krte.. limits ko integrand me daalte hain multiply by limits ki diff..

DLS
 one year ago
Best ResponseYou've already chosen the best response.1medal medal medal medal medal medal medal medal medal medal medal medal medal medal medal medal medal medal medal medal medal medal medal medal medal medal medal medal :*

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.2lol. meri bezti badi achi krte ho aap log. :/

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.0maine upar kuch padha bhi nahi kya likha hai :3

knock
 one year ago
Best ResponseYou've already chosen the best response.0What's the answer then? xD

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.0@yrelhan4 is the answer to all the questions . O:)

knock
 one year ago
Best ResponseYou've already chosen the best response.0Great xD I thought in a way to solve it but if it's already solved then ok (:
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