Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

starkeyfish

  • one year ago

Verify the identity: (1-sinx)/cosx = cosx/(1+sinx)

  • This Question is Closed
  1. RolyPoly
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    LS = (1-sinx)/cosx = 1/cosx - sinx/cosx RS = \(\large\frac{cosx}{1+sinx}\) = \(\large\frac{cosx(1-sinx)}{(1+sinx)(1-sinx)}\) = \( \large\frac{cosx}{1-sin^2x} - \frac{cosxsinx}{1-sin^2x}\) =.... Note: \[1 = cos^2x + sin^2x \]

  2. Jhannybean
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    why is it so tiny!

  3. .Sam.
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Because its a spoiler

  4. starkeyfish
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm very bad at basic math , so I'm finding all of this to be very foreign.

  5. RolyPoly
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Actually, simply working from the left is ok :D \[RS = \frac{cosx}{(1+sinx)}\]\[=\frac{cos}{1+sinx}\times \frac{1-sinx}{1-sinx}\]By the identity a^2 - b^2 = (a+b)(a-b), we get\[=\frac{cos(1-sinx)}{1-sin^2x}\]Then, \(sin^2x+cos^2x =1\) to express \(1-sin^2x\) in terms of \(cos^2x\). Finally, cancel the common factor, and you'll get the left side!

  6. starkeyfish
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so 1-sin^2 = cos^2x?

  7. RolyPoly
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Oh, yes.

  8. starkeyfish
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay, thank you!

  9. RolyPoly
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    You're welcome~~

  10. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.