A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Verify the identity:
(1sinx)/cosx = cosx/(1+sinx)
anonymous
 3 years ago
Verify the identity: (1sinx)/cosx = cosx/(1+sinx)

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0LS = (1sinx)/cosx = 1/cosx  sinx/cosx RS = \(\large\frac{cosx}{1+sinx}\) = \(\large\frac{cosx(1sinx)}{(1+sinx)(1sinx)}\) = \( \large\frac{cosx}{1sin^2x}  \frac{cosxsinx}{1sin^2x}\) =.... Note: \[1 = cos^2x + sin^2x \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm very bad at basic math , so I'm finding all of this to be very foreign.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Actually, simply working from the left is ok :D \[RS = \frac{cosx}{(1+sinx)}\]\[=\frac{cos}{1+sinx}\times \frac{1sinx}{1sinx}\]By the identity a^2  b^2 = (a+b)(ab), we get\[=\frac{cos(1sinx)}{1sin^2x}\]Then, \(sin^2x+cos^2x =1\) to express \(1sin^2x\) in terms of \(cos^2x\). Finally, cancel the common factor, and you'll get the left side!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.