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can you tell me how to at least start it?

|dw:1368859626389:dw|

That's how you start.

can you tell me what the J is for? I have never ever seen that used before

|dw:1368859717310:dw|

J is just a multiplier. In this case, J = 1 , so you can remove it

(x^8+1) means: X^9

I highly doubt that it would be that simple felavin.

WHY? SMOKEYDABEAR.

could the next step be to let u=tan(theta) then du=sec^2(theta) d(theta)

@SinginDaCalc2Blues same thing.........you're looping

Yeah all that would do is put you right back to where you started

^^^ that girl is just too smart..........

Too stupid*

I'm just here to learn how to do it myself

are you people calling me stupid? seriously?

No, I was calling myself stupid xD

no, I didn't mean that.

okay, let's figure out an easier way to solve this problem.

@SinginDaCalc2Blues can you handle recursive integrals?

@SinginDaCalc2Blues we really would never do that.

wait............a minute...why not just polar?

Polar coordinates? Actually that makes some sense...

are you saying turn the integral into a polar expression or something?

my professor is devious!

Your professor is pretty evil for giving you something like this

would u=x^2
du=2x dx
indefinite integral of 1/(u^4+1)
help?
(sorry, my latex isn't working)

@SinginDaCalc2Blues I reduced it to......can you solve this?|dw:1368860855998:dw|

the int, called complex in

uhm if k is a constant, what is J again?

J is the variable of integration, just like U

U in U substitution

I just looked it up on wolfram... what is this monstrosity...

@smokeydabear I told you...........

How do you know where to even start with something like this? That's always been my problem

a good place to start is with Vodka :o)

@SinginDaCalc2Blues I asked you if you knew recursives because as you can see here, the trigs are repeating..which means recursion

no, not vodka, start with despair.

in 30 minutes i will no longer be able to do integration but I will be able to slurrrr Russian! :o)~

vodka inhibits your ability to do math.

despair only temporarily inhibits your ability to do everything

@smokeydabear recursion works to start. for example|dw:1368861204284:dw|

Okay, so how would we use that to help us? I'm still confused :s

crazy problem o:

well long only :P

@smokeydabear it saves time because once you know that it will repeat, you can generalize..........

hey guys...i have an idea...gimme a sec...

.........meaning............|dw:1368861457508:dw|

u = x^2, du = 2x dx\[\int \frac{du}{u^4+1}\]

so, because they occur in trig functions, we can use it for the tan theta

@stamp did that

Ohhhhhh I see what you did with the sin's and the pi's @primeralph very clever! =D

now we just need to learn to use it effectively...

|dw:1368861979382:dw|

I gotcha Ralph, I noticed it too but I didn't want to be mean =P

Does this little bit of trickyness open any doors?

yeah what stamp wrote I believe is wrong...it wouldn't be x^4...it would be (x^4)^2

Well what stamp wrote isn't technically wrong, but it isn't the method to solving this.

I basically factored out of the denominator an x^2...then did u-sub

hello

Then \[u^3+1=(u+1)(u^2-u+1)\], use partial fractions.

what do i do with the numerator?

i havent read much what is written above, its too long, has the question been solved ?

has anyone tried x^2 =t ?

yeah shub...wayyy up at the top...we are past that now...but thanks

Yes @SinginDaCalc2Blues

ok...i will keep plugging away and see if I can get it...this problem has been so crazy! :o)

are you using imaginary numbers shub?

is it a definite/indefinite integral in your original question?

yes, the very same.
i can be treated as just another constant

indefinite

i have no idea how to use imaginary numbers...i'm only in calc 2..we haven't used those

I wish I had learned about them...i just hope i can solve this

@roly Thank you for taking the time to illustrate it.