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anonymous
 3 years ago
How many different 12member juries can be chosen from a pool of 40 people?
I really can't understand this.
anonymous
 3 years ago
How many different 12member juries can be chosen from a pool of 40 people? I really can't understand this.

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mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1And : \(\large ^n C_r = \cfrac{n!}{r! (nr)!} \)

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1@Haruhi , can you solve it now?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0not really. I've been trying to solve it that way all this time. I'm getting weird results.

.Sam.
 3 years ago
Best ResponseYou've already chosen the best response.4From \[\large ^n C_r = \cfrac{n!}{r! (nr)!} = \frac{40!}{12!(4012)!} = \frac{40 \times 39 \times 38 \times...}{(12 \times 11 \times 10 \times ...)(28 \times 27 \times 26 \times ...)}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I get 1.5186643e+48 (whatever that means) and my options are a) 3,586,853,480 b) 4,586,853,480 c) 5,586,853,480 d) 6,586,853,480

.Sam.
 3 years ago
Best ResponseYou've already chosen the best response.4Lol you should get 5,586,853,480 check your calculator

Zarkon
 3 years ago
Best ResponseYou've already chosen the best response.0type "calculate 40 choose 12" into google

Zarkon
 3 years ago
Best ResponseYou've already chosen the best response.0it will take "40 choose 12" and give the answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think we don't have Google in the exam!?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok..... still confused. How can a calculator be wrong lol what the hell am I doing

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Try:\[\frac{40!}{(12!(4012)!)} \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That is wrong all of you I think its 12 times 40 its simple probability i think

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's the right answer, yeah. But it's damn confusing having to work with numbers like 815,915,279,999,999,744,392,488,672,368,848,648,400,776,424,296 _ so I must've made a mistake at some point.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0please dont say dam on a post there are 7th graders in geometry and algebra 2 like me who don't like that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What is that supposed to mean
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